Answer:
- A: 24,500
- B: 11,800
- C: 12,700
Step-by-step explanation:
Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.
The revenue from those seats is, ...
24,500×$30 = $735,000
so the revenue from B and C seats is ...
$1,246,800 -735,000 = $511,800
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We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...
24b +18(24500-b) = 511800
6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms
b = 70,800/6 = 11,800 . . . . . . . seats in B section
24,500 -11,800 = 12,700 . . . . . seats in C section
There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.
Answer:
Solution for 3/4h-12=8(5/8) equation:
Step-by-step explanation:
3/4h-12=8(5/8)
We move all terms to the left:
3/4h-12-(8(5/8))=0
Domain of the equation: 4h!=0
h!=0/4
h!=0
h∈R
Answer:
I will help you wit what you need
Step-by-step explanation:
Answer:
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Step-by-step explanation:
