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3 years ago

13

Martin keeps track of the low temperature every day. On Monday, it was -12˚ On Tuesday, it was -9˚C. What is the difference betw

een the low temperature on Tuesday and the low temperature on Monday?
Group of answer choices
21 C

-21 C

-3 C

3 C

2 answers:

Mama L [17]3 years ago

8 0

Answer:

the answer is -3 c

Step-by-step explanation:

what you do to get -3 is you subtract -12 - -9

<em>Hope this helped and hope its the right answer!</em>

gogolik [260]3 years ago

6 0

The difference is 3 declares Celsius.

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Which are characteristics of the graph of the function f(x) = (x + 1)2 + 22 Check all that apply.

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I can't say that the y intercept is 3 because when you distribute,

$f(x) = (x + 1)2 + 22 \\ f(x) = 2x + 2 + 22 \\ f(x) = 2x + 24$

It seems like the y intercept is 24.

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The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co

julia-pushkina [17]

Answer:

P[X=3,Y=3] = 0.0416

Step-by-step explanation:

Solution:

- X is the RV denoting the no. of customers in line.

- Y is the sum of Customers C.

- Where no. of Customers C's to be summed is equal to the X value.

- Since both events are independent we have:

P[X=3,Y=3] = P[X=3]*P[Y=3/X=3]

P[X=3].P[Y=3/X=3] = P[X=3]*P[C1+C2+C3=3/X=3]

P[X=3]*P[C1+C2+C3=3/X=3] = P[X=3]*P[C1=1,C2=1,C3=1]

P[X=3]*P[C1=1,C2=1,C3=1] = P[X=3]*(P[C=1]^3)

- Thus, we have:

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P[X=3,Y=3] = 0.0416

6 0

3 years ago

Ket [755]

Answer:

The value of 4 is an input of the function

Step-by-step explanation:

Let

x -----> the independent variable or input value

y ----> the dependent variable or output value

we know that

Looking at the graph

The domain (input values) of the linear function is equal to the interval

[1,∞)

$x\geq 1$

All real numbers greater than or equal to 1

The range (output values) of the linear function is equal to the interval

(-∞,3]

$y\leq 3$

All real numbers less than or equal to 3

therefore

The value of 4 is an input of the function

6 0

3 years ago

Read 2 more answers

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago