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2 years ago

Which functions have graphs that are less steep than the graph of f(x)= -4x^2

1 answer:

8 0

TTese are all parabolas whose axis of symmetry is the y axis. The negative coefficient means they open downwards and the positive mean they open upwards. The higher the absolute value of the coefficient is the greater the slope, so 2x^2 will be steeper than x^2 and -4x^2 will be steeper than - 2x^2.

So h(x) and j(x) are the answers.

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I need help with this!!! Thank you

ruslelena [56]

Answer:

4n^3-n^2-5n

Step-by-step explanation:

n(2n+4n2−5−3n)

=(n)(2n+4n2+−5+−3n)

=(n)(2n)+(n)(4n2)+(n)(−5)+(n)(−3n)

=2n2+4n3−5n−3n2

=4n3−n2−5n

6 0

2 years ago

3. the answer isn't c or d

Kay [80]

Answer:

A. Yes; no vertical line passes through two graphed points

Step-by-step explanation:

3 0

2 years ago

Mr. Smith ate a snack with 80.79 total calories. If the chips he ate were 43.39 calories, how

Paul [167]

Answer:

37.40 calories

Hope this helps :)

4 0

3 years ago

Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.