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3 years ago

I REALLY NEED HELP PLS!!! Devon earned $42,500 last year and spent 12% of it on home repairs. How much did he spend on his home?

Mathematics

1 answer:

Artist 52 [7]3 years ago

3 0

Answer:

$47,600 Spent on home repairs

Step-by-step explanation:

So we know that Devon is spending 12 percent of the home cost on repairs

We know the home cost is 42,500

So we just add 12 percent to the bundle

We know 42,500 is 100 percent of the price

And we want to add another 12 percent since the question is asking for the total amount spent on homes

So initially we just multiply 42,500 by 112% or 1.12

Now just multiply

You’ll get 47,600

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When it was 70 degrees outside, 50 members showed up at a beach club. For each degree the temperature rose, another 10 members c

strojnjashka [21]

The function f(t), that represents the number of members at the beach club as a function of the temperature is f(t) = 10t + 50

<u>Solution:</u>

Given that, When it was 70 degrees outside, 50 members showed up at a beach club.

For each degree the temperature rose, another 10 members came to the beach club.

We have to write the function, f(t), that represents the number of members at the beach club as a function of the temperature.

Now, according to the given information,

Initially 50 members and then, members keep on adding by rise in temperature,

So, 50 + t x 10 [ t represents change in temperature, and 10 is number of people who joins club ]

Then, f(t) = 10t + 50.

Hence, the function is f(t) = 10t + 50

3 0

3 years ago

Using 7 four times and 1 one time getting to 100

777dan777 [17]

Answer:

So the answer is $(7+\frac{1}{7} )\times (7+7)=100$

Step-by-step explanation:

Given,

Using $7$ four times and $1$ one time getting to $100$

If we are write this way then easily get the answer;

$(7+\frac{1}{7} )\times (7+7)$

Add together $7+\frac{1}{7}$ by making a common denominator of $7$ and also add $(7+7)$ in the second set of parenthesis to yield $14$

$(\frac{49+1}{7} )\times 14$

$\frac{50}{7} \times 14$

$50\times 2$ (By Cross-reduce and multiply the fractions)

$100$

∴ $(7+\frac{1}{7} )\times (7+7)=100$

4 0

3 years ago

Match the parabolas represented by the equations with their foci.

Elenna [48]

Function 1 $f(x)=- x^{2} +4x+8$

First step: Finding when $f(x)$ is minimum/maximum
The function has a negative value $x^{2}$ hence the $f(x)$ has a maximum value which happens when $x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2$ . The foci of this parabola lies on $x=2$ .

Second step: Find the value of y-coordinate by substituting $x=2$ into $f(x)$ which give $y=- (2)^{2} +4(2)+8=12$

Third step: Find the distance of the foci from the y-coordinate
$y=- x^{2} +4x+8$ - Multiply all term by -1 to get a positive $x^{2}$
$-y= x^{2} -4x-8$ - then manipulate the constant of y to get a multiply of 4
$4(- \frac{1}{4})y= x^{2} -4x-8$
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is $12- \frac{1}{4}=11.75$

Hence the coordinate of the foci is (2, 11.75)

Function 2: $f(x)= 2x^{2}+16x+18$

The function has a positive $x^{2}$ so it has a minimum

First step - $x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4$
Second step - $y=2(-4)^{2}+16(-4)+18=-14$
Third step - Manipulating $f(x)$ to leave $x^{2}$ with constant of 1
$y=2 x^{2} +16x+18$ - Divide all terms by 2
$\frac{1}{2}y= x^{2} +8x+9$ - Manipulate the constant of y to get a multiply of 4
$4( \frac{1}{8}y= x^{2} +8x+9$

So the distance of focus from y-coordinate is $\frac{1}{8}$ to the north of $y=-14$
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: $f(x)=-2 x^{2} +5x+14$

First step: the function's maximum value happens when $x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25$
Second step: $y=-2(1.25)^{2}+5(1.25)+14=17.125$
Third step: Manipulating $f(x)$
$y=-2 x^{2} +5x+14$ - Divide all terms by -2
$-2y= x^{2} -2.5x-7$ - Manipulate coefficient of y to get a multiply of 4
$4(- \frac{1}{8})y= x^{2} -2.5x-7$
So the distance of the foci from the y-coordinate is - $\frac{1}{8}$ south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when $x=8.5$ and $y=79.25$ . The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when $x=-2.75$ and $y=-10.125$ . Manipulating coefficient of y, the distance of foci from y-coordinate is $\frac{1}{8}$ to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when $x=1.5$ and $y=9.5$ . The distance of the foci from the y-coordinate is $\frac{1}{8}$ to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

8 0

3 years ago

- 6 * 1/3=?please type the equation and simplify if possible

rosijanka [135]

We have to simplify this as a product of fractions. Notice that the 6 has a negative sign, therefore, the result will be negative. We have then: