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nikitadnepr [17]
3 years ago
15

Olivia is going to invest $32,000 and leave it in an account for 15 years. Assuming the interest is compounded monthly, what int

erest rate, to the nearest hundredth of a percent, would be required in order for Olivia to end up with $80,000?
Mathematics
1 answer:
Sliva [168]3 years ago
6 0

Answer:

6.12

Step-by-step explanation:

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SOMEONE PLEASE HELP!
Andrews [41]

Answer:

17.2°

Explanations

To find angle A, use the cosine rule.

a^2 = b^2 + c^2 - 2 × a × c cos A

4^2 = 7^2 + 10^2 - 2 × 7 × 10 cos A

16 = 49+ 100 - 140 × cosA

16 = 149 - 140cosA

16- 149 = - 140cosA

-133 = - 140cosA

cosA = 133/140

cosA = 0.95

A = 17.2°

7 0
2 years ago
ASAP HELPPP PLZZZZZ hurry plzzz
sleet_krkn [62]

Answer:

It's an enlargement

Step-by-step explanation:

e.g. when your pupils become dilated they enlarge

5 0
3 years ago
Read 2 more answers
-2x-5y=3 3x-8=-6 solve by substition
ELEN [110]
Maybe use photo math i guess
6 0
3 years ago
Read 2 more answers
How do you do series with an n
SOVA2 [1]
The problem can be solved step by step, if we know certain basic rules of summation.  Following rules assume summation limits are identical.
\sum{a+b}=\sum{a}+\sum{b}
\sum{kx}=k\sum{x}
\sum_{r=1}^n{1}=n
\sum_{r=1}^n{r}=n(n+1)/2

Armed with the above rules, we can split up the summation into simple terms:
\sum_{r=1}^n{40r-21n+8}=n
=40\sum_{r=1}^n{r}-21n\sum_{r=1}^n{1}+8\sum_{r=1}^n{1}
=40\frac{n(n+1)}{2}-21n^2+8n
=20n(n+1)-21n^2+8n
=28n-n^2

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n 
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0  therefore f(14) is a maximum
(b) f(x) is a maximum when n=14

(c) the maximum value of f(x) is f(14)=196
4 0
3 years ago
ANSWER ASAP: New machine has productivity (measured in the number of produced details) 12% greater than the last model. After re
GREYUIT [131]
The total number of produced details increased by 6.4%

suppose the starting number was x. 
suppose x=100
100 +12%= 112
112-5%=106.4
106.4-100=6.4
6.4%

4 0
4 years ago
Read 2 more answers
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