3 years ago

. Complete the Venn diagram to show

1 answer:

4 0

15 is a common factor and you need to show the vent diagram for me to be able to complete it

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Arada [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

slavikrds [6]

Answer:

Step-by-step explanation:

no,

it is not in the form

$ax {}^{2} + bx + c = 0$

5 0

3 years ago

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

8 0

3 years ago

azamat

To be parallel with that line the equation has to have the same slope as the equation given, like y = 10x + 3.

3 0

3 years ago

Mrrafil [7]

Your answer is x = 78! Hope this helps!

3 0

3 years ago