The ionization energy is 1 × 10^-18 J
<h3>What is ionization energy?</h3>
The ionization energy is the energy required to remove an electron from an atom.
We have the following information;
wavelength of the photon = 58.4 nm
Speed of the electron = 2310 × 10^3 m/s
Since;
hv = I + 1/2mv^2
v = c/λ
hc/λ = I + 1/2mv^2
I = hc/λ - 1/2mv^2
I = (6.6 × 10^-34 × 3 × 10^8/58.4 × 10^-9) - (1/2 × 9.11 × 10^-31 × (2310 × 10^3)^2)
I = 1 × 10^-18 J
Learn more about ionization energy: brainly.com/question/16243729
The octet rule is that atoms must have 8 valence electrons to have an octet. Usually, when atoms have an octet, they tend not to bond with any other atoms because they are already stable and do not need to bond anymore.
Answer:
31.64...
Explanation:
The formula is volume is equal to mass over density.
So 25/0.79=31.64...
Answer:
0.56 M
Explanation:
Step 1: Given data
- Rate constant (k): 0.035 s⁻¹
- Initial concentration of the reactant ([A]₀): 1.5 M
Step 2: Calculate the amount of reactant ([A]) after 28 seconds
For a first-order kinetics, we will use the following expression.
ln [A] = ln [A]₀ - k × t
ln [A] = ln 1.5 - 0.035 s⁻¹ × 28 s
[A] = 0.56 M