Answer : The oxidation state of nitrogen in
is, (+5)
Explanation :
Rules for the oxidation numbers :
- The oxidation number of a free element is always be zero.
- The oxidation number of a monatomic ion equal to the charge of the ion.
- The oxidation number of Hydrogen (H) is +1.
- The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in the peroxides.
- The oxidation number of a Group 1 element in a compound is +1.
- The oxidation number of a Group 2 element in a compound is +2.
- The oxidation number of a Group 17 element in a binary compound is -1.
- The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
- The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given compound is,
Let the oxidation state of 'N' be, 'x'
Hence, the oxidation state of N is, (+5)
The breakdown of mass percentage of the elements is determined by dividing molar masses to the total molar mass of the compound (246.37 g/mol). There are four elements: for Mg: 9.87%, S:13.01%, H:5.69%, 71.44%.
The answer would be A. which says the emitter- base junction must be forward biased, and the collector- base junction must be reverse biased.
The type of structural isomerism arises when a particular ligand is capable of coordinating to a metal in two ways is linkage isomer.
<h3>What are structural isomerism?</h3>
Structural isomerism is a kind of isomerism in which molecular formula of the compound is same but they all have different arrangement of atoms or bonding in them.
If in any compound particular ligand is attached to the metal through different sides of the compound, then the product which is formed by these arrangement is known as linkage isomers.
Example of the linkage isomer is attached below.
Hence, the required isomerism is linkage isomerism.
To know more about structural isomerism, visit the below link:
brainly.com/question/15183293
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