V + f − e = 2
<span>Add -2+e to both sides. </span>
<span>v + f − e -2+e = 2 -2+e </span>
<span>On simplification, we get </span>
<span>v + f − 2 = e </span>
<span>Yes, that is the solution for e.</span>
Answer:
Do you have the a picture of the table
Answer:
a=5, b=-2
Step-by-step explanation:
If you simplify the equation, you get:
3ax +6 -4x -4b - 11x - 14 = 0 =>
3ax - 15x -4b -8 = 0
group together x's and constants:
(3a-15)x -8 -4b = 0
To make this 0 for all x, we have to find an a such that 3a-15 = 0 and b such that -8-4b = 0. this leads to a=5, b=-2
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
Answer:
D) 0.1250
Step-by-step explanation:
Let P(J) = Probability of John to purchase 0 books
Let P(B) = Probability of Beth to purchase 0 books
P(J∩B) = Probability that both john and Beth will purchase 0 books .ie. a total of 0 books is purchased.
Since the decisions to purchase books are two independents events,
P(J∩B) = P(J) * P(B)
P(J) = 0.5
P(B) = 0.25
P(J∩B) = 0.5 * 0.25
P(J∩B) = 0.125
