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4 years ago

Complete the pattern 5,10,30,60,180,__

Mathematics

2 answers:

nalin [4]4 years ago

7 0

Hi!

If the pattern starts off with 5 going to 10, then that would be multiplying by 2. Then, from 10 to 30 would be multiplying by 3. From 30 to 60 would be 2, and 60 to 180 would be 3. So, the pattern is multiply by 2, then multiply by 3, then by 2, then by 3, and so on. So, if we multiply 180 by 2, we get 360, the answer.

Hope this helps!

jok3333 [9.3K]4 years ago

3 0

270 because you can realize it starts going up by 30 so you had to multiply 3 × 30 to get 90 then add 90 to 180 and get 270

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777dan777 [17]

Answer:

160,000 sq ft

Step-by-step explanation:

2018 is 13 years after 2005.

Put x=13 in the equation and evaluate:

... y = 0.538·13 +9.02 = 6.994 +9.02 = 16.014

This is the number of 10,000 sq ft, so the required area is ...

... 16 times 10,000 sq ft = 160,000 sq ft.

4 0

3 years ago

6 people equally share 56 gummy worms. How many gummy worms does each person get? Nine and one sixth gummy worms nine and two si

riadik2000 [5.3K]

Answer:

nine and two sixths gummy worms

Step-by-step explanation:

54/6 = 9

56 - 54 = 2

so answer:

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3 years ago

Who can help me needed for tomorrow please

blagie [28]

a) 170.00 =8n -30

200= 8n

n = 200/8 = 25 items

b) since the expenses increased the profits would decrease

profit = 8(25)-40 = 200-40 = 160

170-160 = 10.00

profit decreased by $10.00

6 0

4 years ago

Read 2 more answers

Solving for matrices

muminat

Answer:

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)$

Multiply the first row by 5, the second row by -3 and add these two rows:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)$

Subtract the third row from the second:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)$

Divide the third row by 6:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)$

Now multiply the third equation by 26 and add it to the second row:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)$

You get the system of three equations:

$\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.$

From the third equation

$z=\dfrac{90}{45}=2.$

Substitute z=2 into the second equation:

$-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.$

Now substitute z=2 and y=5 into the first equation:

$3x-4\cdot 5-5\cdot 2=-27\\ \\3x-20-10=-27\\ \\3x-30=-27\\ \\3x=-27+30=3\\ \\x=1.$

The solution is (1,5,2)

4 0

3 years ago

Given log630 ≈ 1.898 and log62 ≈ 0.387, log615 =

Tom [10]

$\log_630\approx1.898\\\\\log_62\approx0.387\\\\\log_615=\log_6\dfrac{30}{2}=\log_630-\log_62\approx1.898-0.387=1.511\\\\Used:\\\\\log_ab-\log_ac=\log_a\dfrac{b}{c}$

6 0

3 years ago

Read 2 more answers