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docker41 [41]
3 years ago
7

Using the distributive property simplify this -2(x-3)

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

For this case we must simplify the following expression:

-2 (x-3)

By definition we have that the distributive property establishes that:

a (b + c) = ab + ac

So, if we have:

-2 (x-3)

We take into account the law of multiplication of signs:

- * + = -\\- * - = +

So:

-2 (x-3) = - 2x + 2 * 3 = -2x + 6

Answer:

-2x + 6

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Based on the model ​N(11541154​,8686​) describing steer​ weights, what are the cutoff values for ​a) the highest​ 10% of the​ we
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Answer:

a) x = 1225.68

b) x = 1081.76

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Step-by-step explanation:

Given:

- Th random variable X for steer weight follows a normal distribution:

                                    X~ N( 1154 , 86 )

Find:

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b) the lowest​ 20% of the​ weights? ​

c) the middle​ 40% of the​ weights? ​

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a)

We will compute the corresponding Z-value for highest cut off 10%:

                                   Z @ 0.10 = 1.28

                                    Z = (x-u) / sd

Where,

u: Mean of the distribution.

s.d: Standard deviation of the distribution.

                                   1.28 = (x - 1154) / 86

                                      x = 1.28*86 + 1154

                                      x = 1225.68

b)

We will compute the corresponding Z-value for lowest cut off 20%:

                                   -Z @ 0.20 = -0.84

                                    Z = (x-u) / sd

                                   -0.84 = (x - 1154) / 86

                                      x = -0.84*86 + 1154

                                      x = 1081.76

c)

We will compute the corresponding Z-value for middle cut off 40%:

                                    Z @ 0.3 = -0.52

                                    Z @ 0.7 = 0.52

                                    [email protected] < x < [email protected]

                       -.52*86 + 1154 < x < 0.52*86 + 1154

                                  1109.28 < x < 1198.72

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Step-by-step explanation:

Hi, Hope this will help:)

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