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3 years ago

Using the distributive property simplify this -2(x-3)

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

4 0

For this case we must simplify the following expression:

$-2 (x-3)$

By definition we have that the distributive property establishes that:

$a (b + c) = ab + ac$

So, if we have:

-2 (x-3)

We take into account the law of multiplication of signs:

$- * + = -\\- * - = +$

So:

$-2 (x-3) = - 2x + 2 * 3 = -2x + 6$

Answer:

$-2x + 6$

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What is the constant of variation, k, of the direction variation, y = kx, through (-3, 2)

Bond [772]

$\bf \qquad \qquad \textit{direct proportional variation}
\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
(\stackrel{x}{-3},\stackrel{y}{2})\textit{ we also know that }
\begin{cases}
x=-3\\
y=2
\end{cases}\implies 2=k(-3)\implies \cfrac{2}{-3}=k$

8 0

4 years ago

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What would these be reflected as?

pantera1 [17]

what direction are they to be reflected

Step-by-step explanation:

answers will be different depending on that

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2 years ago

Two crossroads, each of width 5 m, run at right angles through the centre of

DerKrebs [107]

550 sq m

Step-by-step explanation:

Step 1 :

The length of the first cross road the park is 70 m

The width of the first cross road the park is 5 m

So its area is 70 * 5 = 350 sq m

Step 2 :

The length of the second cross road the park is 45 m

The width of the width cross road the park is 5 m

So its area is 45 * 5 = 225 sq m

Step 3 :

The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m

This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park

So we have

the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m

8 0

3 years ago

Tanya spent 1/5 of her allowance on candy and 2/3 on food. What fraction of her allowance did Tanya spend on food and candy alto

kari74 [83]

13/15 of her allowance was spent in total.

To solve this, you'd need to find the least common denominator (LCD) so that both fractions have the same number on the bottom. In this case, the first number that you could get with 5 and 3 was 15.

Next, you'd have to multiply the numerator by the same amount as the denominator, so that the fractions are proportionate. So, for 1/5, since we had to multiply 5 by 3 to get 15, we'd multiply 1 by 3 as well, giving us 3/15. Doing the same with 2/3, we'd get 10/15.

Then, you add the two fractions together (10/15 + 3/15 = 13/15).

Now, in any other case, you could probably simplify the fraction after you've solved the problem. If we got 12/15 instead of 13/15, then we could simplify that to 4/5, since both 12 and 15 are divisible by 3. But in this case, this is the simplest form of that fraction.

Hope this helped!!!

8 0

3 years ago

What’s the inverse of y= 100 - x^2

Marianna [84]

Answer:

The inverse is ±sqrt(100-x)

Step-by-step explanation:

y= 100 - x^2

Exchange x and y

x = 100 -y^2

Solve for y

Subtract 100 from each side

x-100 = 100-100-y^2

x-100 = - y^2

Multiply by -1

-x+100 = y^2

100 -x = y^2

Take the square root of each side

±sqrt(100-x) = sqrt(y^2)

±sqrt(100-x) = y

The inverse is ±sqrt(100-x)

3 0

4 years ago

Read 2 more answers