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anyanavicka [17]
3 years ago
13

you have a big bag of 17 marbles for our blue sticks are green 2 are red and the others are yellow what is the probability of dr

awing a red marble putting it aside and then drawing a green marble?
Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

  • 3/68

Step-by-step explanation:

<u>Given</u>

  • Total 17 marbles
  • 4 - blue marbles
  • 6 - green marbles
  • 2 - red marbles
  • The rest - yellow marbles

<u>Probability of drawing red first:</u>

  • P(red) = number of red / total number = 2/17

<u>Probability of drawing green second, without replacement:</u>

  • P(green) = number of green / number left in the bag = 6/16 = 3/8

<u>Probability of red and green in order:</u>

  • P = P(red)*P(green) = 2/17*3/8 = 3/68

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Calculate the expected value, the variance, and the standard deviation of the given random variable X. (Round all answers to two
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Answer:

E (X) = 1.8

Var (X) = 0.36

σ = 0.6

Step-by-step explanation:

Solution:-

- Denote the random variable X : is the number of red marbles that Suzan has in her hand after she selects three marbles.

- Total sample space (bag) have the following quantity of colored marbles:

                Bag : { 3 Red , 2 Green }

- Suzan selects three marbles from the bag. The Event (X) defines the number of red marbles out of 3.

- The total number of outcomes / selections for randomly selecting 3 balls from the bag:

               All outcomes = 5 C 3 = 10

- The probability distribution of the random variable X, we will use combinations to determine the required probabilities:

  X = 1 red marble:

        P ( X = 1 ) : Suzan chooses 1 Red marble from the available 3 red marble and 2 green marbles.

        P ( X = 1 ) = [ 3C1*2C2 ] / all outcomes = (3*1) / 10 = 0.3

X = 2 red marble:

        P ( X = 2 ) : Suzan chooses 2 Red marble from the available 3 red marble and 1 green marbles.

        P ( X = 2 ) = [ 3C2*2C1 ] / all outcomes = (3*2) / 10 = 0.6

X = 3 red marble:

        P ( X = 3 ) : Suzan chooses 3 Red marble from the available 3 red marble.

        P ( X = 3 ) = [ 3C3] / all outcomes = (1) / 10 = 0.1

- The probability distribution is as follows:

          X :         1                 2                3

       P (X):       0.3            0.6              0.1

- The expected value E(X) for the given random variable X is:

                E ( X ) = ∑Xi*P(Xi)

                           = 1*0.3 + 2*0.6 + 3*0.1

                           =1.8

- The variance Var(X) for the given random variable X is:

                Var ( X ) = ∑Xi^2*P(Xi) - [ E(X) ] ^2

                               = 1^2*0.3 + 2^2*0.6 + 3^2*0.1 - 1.8^2

                               = 0.36

- The standard deviation for the given random variable X is:

                σ = √Var(X)

                σ = √0.36

                σ = 0.6

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