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Tom [10]
3 years ago
13

The drama club is having a fundraiser selling novelty cups. Their goal is to make a profit of $1000. If they receive $3.50 profi

t for each cup (c), how many cups do they need to sell to make a profit of $1000?
Which equation could be used to find c, the number of cups they need to sell?

A) $3.50+c=$1000
B) $3.50-c=$1000
C) $1000-$3.50=c
D) $1000/$3.50=c​
Mathematics
1 answer:
zlopas [31]3 years ago
4 0
The answer is D because using division you would find how many cups you need to sell.
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y = x - 3
y = -1 - 3
y = -4

solution is (-1,-4)
===================
35. -6 = -x - 2y
      x = -2y + 6

2 + 5x = -2y
2 + 5(-2y + 6) = -2y
2 - 10y + 30 = -2y
32 = -2y + 10y
32 = 8y
32/8 = y
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2 + 5x = -2y
2 + 5x = -2(4)
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36. 4x + 6y = 2000
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37. 4x + 6y = 2000
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3 0
3 years ago
What is 5/10 + 2/10 ?
Daniel [21]

Step-by-step explanation:

5/10+2/10

7/10

0.7

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4 0
3 years ago
I need help with number 5
Zielflug [23.3K]

Answer:

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Step-by-step explanation:

You will need to move the decimal point to the right one place

5 0
3 years ago
What’s the x on this triangle ?
Dmitry [639]

Answer:

x = 5

Step-by-step explanation:

x is the length of the hypotenuse of this triangle.  The length of one of the legs of the triangle is 3" and that of the other leg is 4".

Applying the Pythagorean Theorem:  x^2 = 3^2 + 4^2, or 25

Thus, the length x is +√25, or 5.

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7 0
2 years ago
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

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  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
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So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
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