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3 years ago

What would the equation be ?

Mathematics

1 answer:

Vikentia [17]3 years ago

4 0

Answer:

y = 4/5x-18/5

Step-by-step explanation:

First we find the slope from the given points (-3,-6) (2,-2)

m = (y2-y1)/(x2-x1)

m = (-2 - -6)/(2 - -3)

(-2+6)/( 2+3)

4/5

The slope intercept form of an equation is

y = mx +b where m is the slope and b is the y intercept

y = 4/5 x +b

Substitute a point into the equation to find b

-6= 4/5(-3) +b

-6= -12/5 +b

Add 12/5 to each side

-6 +12/5 = -12/5 +12/5 +b

Get a common denominator

-30/5 + 12/5 = b

-18/5 =b

The equation is

y = 4/5x-18/5

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iVinArrow [24]

Step-by-step explanation:

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3 0

2 years ago

Zebediah is an American traveling with a tour group in Eastern Europe. During a stop in Rommania, he purchases a souvenir that i

denis23 [38]

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5 0

2 years ago

What happens to the Law of Cosines if the known angle is 90 degrees?

poizon [28]

Answer:

See below.

Step-by-step explanation:

It transforms to the Pythagoras theorem.

c^2 = a^2 + b^2 - 2ab cos C

If C = 90, cos C = zero so the last term disappears.

c^2 = a^2 + b^2 - 2ab * 0

c^2 = a^2 + b^2.

8 0

3 years ago

Find the equation of the line passing through the points (3,-2) and (4,6) in slope intercept form.

noname [10]

Hey!

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They already give us the slope, so we can solve the y-intercept.

We can use (3, -2).

y = 8x + b

-2 = 8(3) + b

-2 = 24 + b

-2 - 24 = 24 + b - 24

-26 = b

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Hence, the answer is $\Large\boxed{\mathsf{y~=~8x~+~-26}}$

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Hope This Helped! Good Luck!

4 0

3 years ago

What is the slope of the line that is perpendicular to the line that passes through (-2, 7) and (4, 9)? Type a numerical answer

kodGreya [7K]

Answer:

Therefore $m_{2}$ = -3.

Step-by-step explanation:

i) let us say the slope of the line passing through (-2,7) and (4,9) is $m_{1}$ .

ii) to find the slope of the line passing through two points ( $x_{1}$ , $y_{1}$ ) and ( $x_{2}$ , $y_{2}$ ) we use the formula m = $\dfrac{y_{2} - y_{1} }{x_{2} - x_{1} }$ . Therefore we can say that $m_{1}$ = $\dfrac{9 - 7}{4 - (-2)}$ = $\dfrac{1}{3}$ .

iii) let us say the slope of the perpendicular line to the line passing through (-2,7) and (4,9) is $m_{2}$

iv) from the formula for the slopes of a line and the line perpendicular to it which is given by $m_{1}$ × $m_{2}$ = -1, therefore $m_{2}$ = -1 ÷ $m_{1}$ = -3. Therefore $m_{2}$ = -3

6 0

3 years ago