Mass of SiC = 2 g
<h3>Further explanation</h3>
Given
Reaction
SiO₂(s) + 3C(s) → SiC(s) + 2CO(g)
3.00 g of SiO₂
4.50 g of C
Required
mass of SiC
Solution
mol SiO₂ (MW=60,08 g/mol) :
= 3 g : 60.08 g/mol
= 0.0499
mol C(Ar = 12 g/mol) :
= 4.5 g : 12 g/mol
= 0.375
mol : coefficient of reactants =
SiO₂ : 0.0499/1 = 0.0499
C : 0.375/3 = 0.125
SiO₂ as a limiting reactant(smaller ratio)
Mol SiC based on mol SiO₂ = 0.0499
Mass SiC :
= mol x MW
= 0.0499 x 40,11 g/mol
= 2 g
Answer:
Boiling of a substance
Explanation:
When something is boiled, heat is released to the surrounding, making it an exothermic reaction (a type of chemical reaction)
Third quarter (or last quarter)
To solve this we assume
that the gas is an ideal gas. Then, we can use the ideal gas equation which is
expressed as PV = nRT. At a constant temperature and number of moles of the gas
the product of PV is equal to some constant. At another set of condition of
temperature, the constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 V1 / P2
V2 = 153 x 3.00 / 203
<span>V2 = 2.26 L</span>
Answer:
Let's say we were Subtracting 3-2=? To Find the Answer we would Subtract 2 from 3 which is 1 Simple our answer is 1 But let's say the Question is 3 - 1= ? to find this answer we would subtract 1 from 3 which is 2 Let's say you were subtracting 3-3=? to do this we take 3 away from 3 now 3 is 0 so our answer is 0 so there are 3 different problems we can make with 3 we could make more but I'm just telling the basics Hope I Helped Bye :)
Explanation:
