Steroids are like hormones that
greatly influences bodily activities mostly in growth and function. These
functions may modify, change and control one’s body organs or system that’ll
vary in form, shape or structure due to these hormone-like compounds and also,
it can affect one’s psychological and neurological state. There are several
types of steroids. Examples can include:
<span><span>
1. </span>Sex steroids. These are can influence reproduction and
sex characteristics.</span>
<span><span>
2. </span>Anabolic steroids. Most abused in many athletic
activities. These steroids are used for muscle and bone growth. </span>
Answer: electrons
Explanation: Electrons have a charge of -1 each. If two left, the remaining atom would have a positive +2 change.
Assuming the concentration of stock solution is 50% sodium phosphate buffer solution, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.
<h3>What volume of a stock Sodium phosphate buffer and water is needed to 12 mL of 25% sodium phosphate buffer of pH 4?</h3>
The process of preparing solutions from stock solutions of higher concentration is known as dilution.
Dilution is done with the aid of the dilution formula given below:
where
- C1 is the concentration of stock solution
- V1 is the volume of stock solution required to prepare a diluted solution
- C2 is the concentration of the diluted solution prepared
- V2 is the final volume of the diluted solution
From the data provided:
C1 is not given
V1 is unknown
C2 = 25%
V2 = 12 mL
- Assuming C1 is 50% solution
Volume of stock, V1, required is calculated as follows:
V1 = C2V2/C1
V1 = 25 × 12 /50
V1 = 6 mL
Therefore, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.
Learn more about dilution formula at: brainly.com/question/7208546
Answer:
5010J
Explanation:
The following data were obtained from the question:
Mass (m) = 15g
Heat of fusion (ΔHf) = 334J/g
Heat required (Q) =..?
The heat energy required to melt the ice can be obtained as follow:
Q = m·ΔHf
Q = 15 x 334
Q = 5010J
Therefore, the heat energy required to melt the ice is 5010J.
The first one will be 2 1 -> 2 1
Second is 2 3 -> 6 1
