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Mariulka [41]
3 years ago
15

Identify each statement as true or false. Explain in every case.a.Ionization energies are always negative quantities.b.Oxygen ha

s a larger first ionization energy than F.c.The second ionization energy of an atom is always greater than its first ionization energy.d.The third ionization energy is the energy needed to remove three electrons from a neutral atom.
Chemistry
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

(a) FALSE

(b) FALSE

(c) TRUE

(d) FALSE

Explanation:

Ionization energy refers to the energy needed for removal of a valence electron present in valence shell of a gaseous atom.

(a) <u>The value of ionization energy of an atom is always</u><u> positive</u>. This is because energy has to be always supplied or provided to a gaseous atom for the removal of the valence electron.

<em><u>Therefore, the statement (A) is</u></em><em><u> false</u></em>

   

(b) The ionization energy of an atom <u>increases across a period</u> i.e. from left to right. This is because the <u>effective nuclear charge that is experienced by the valence electron increases</u> from left to right in the periodic table, as the atomic number increases.

So, more energy is required to remove the valence electron of fluorine as compared to oxygen.

<u>Therefore, the </u><u>ionization energy of fluorine is greater than oxygen</u><u>.</u>

<em><u>Therefore, the statement (B) is</u></em><em><u> false</u></em>

(c) <u>First ionization energy</u> is energy needed for removal of first electron present in valence shell of a neutral atom. Whereas, <u>second ionization energy</u> is the energy needed for removal of second electron present in valence shell of a monovalent cation

The second ionization energy of an atom is always greater than the first ionization energy. This is because removing<u> an electron from a positively charged species, requires more energy.</u>

<em><u>Therefore, the statement (C) is</u></em><em><u> true</u></em>

<em><u /></em>

(d) <u>The third ionization energy </u>refers to the energy needed to remove the third electron from a divalent cation.

<em><u>Therefore, the statement (D) is</u></em><em><u> false</u></em>

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Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?
sveticcg [70]

Density is the ratio of mass to the volume.

The mathematical expression is given as:

density=\frac{mass}{volume}

Now, density of isooctane = 0.692 g/mL

Volume  = 3.8 gal

Since, 1 gallon = 3.78 L

So, 3.8 gal = 3.78 L\times 3.8

= 14.364 L

As, 1 L = 1000 mL

Therefore, 14.364 L= 14.364 L\times 1000 mL

Volume in mL = 14364 mL

Put the values,

0.692 g/mL=\frac{mass}{14364 mL}

m = 0.692 g/mL\times 14364 mL

= 9939.888 g

Hence, mass of 3.8 gal of the gasoline is 9939.888 g.



6 0
3 years ago
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical rea
Aleksandr [31]

Answer:

ΔS° = - 47.2 J/mol.K

Explanation:

  • P4O10 + 6H2O → 4H3PO4

ΔS°= 4(S°mH3PO4) - 6(S°mH2O) - S°mP4O10

∴ S°mH2O(l) = 69.9 J/mol.K

∴ S°mP4O10 = 231 J/mol.K

∴ S°mH3PO4 = 150.8 J/mol.K

⇒ ΔS° = 4*(150.8) - 6*(69.9) - 231

⇒ ΔS° = - 47.2 J/mol.K

5 0
3 years ago
Read 2 more answers
if three oxygen particles are needed to form ozone, how many units of ozone could be formed from 6 oxygen particles? from 9? fro
tensa zangetsu [6.8K]
<h3>Answers:</h3>

             1) 2 Units of Ozone

             2)  3 Units of Ozone

              3)  9 Units of Ozone

<h3>Solution:</h3>

1)  From 6 Oxygen Particles;

As given,

                          3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      6 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (6 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  2 Units of Ozone

2) From 9 Oxygen Particles;

As given,

                           3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      9 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (9 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  3 Units of Ozone

3)  From 27 Oxygen Particles;

As given,

                             3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      27 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (27 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  9 Units of Ozone

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What happens when you drop iodine on a leaf?
insens350 [35]
When you drop iodine on a leaf you may observe a colour change of orange/brown to a blue/black complex.

This is because in the leaf there are starch molecules that form a blue/black complex with the starch molecules.

hope that helps :)
6 0
3 years ago
Suppose you need to prepare 141.9 mL of a 0.223 M aqueous solution of NaCl. What mass of NaCl do you need to use to make the sol
Afina-wow [57]

Answer:

1.811 g

Explanation:

The computation of the mass need to use to make the solution is shown below:

We know that molarity is

Molarity = \frac{Number\ of\ moles}{Volume\ in\ L}

So,

Number\ of\ moles = Molarity\ \times Volume\ in\ L

= 0.223\times 0.141

= 0.031 moles

Now

Mass = moles \times Molecualr\ weight

where,

The Molecular weight of NaCl is 58.44 g/mole

And, the moles are  0.031 moles

So, the mass of NaCL is

= 0.031 \times 58.44

= 1.811 g

We simply applied the above formulas

3 0
3 years ago
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