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Anestetic [448]
3 years ago
13

Find the formula mass (molecular mass) of propanol: C3H6O ​

Chemistry
1 answer:
malfutka [58]3 years ago
5 0

Answer:

                     Formula mass  =  58.09 g

Explanation:

                    Formula mass of a given molecule is defined as the sum of atomic masses of elements forming the empirical formula of that molecule.

                     In order to calculate the formula mass of propanol, following data is required;

Empirical Formula of Propanol:

                                                   The empirical formula of Propanol is C₃H₆O (also the molecular formula) as it is the lowest possible atomic ratio of the given elements.

Atomic Masses of Elements:

                      Carbon  =  12.01 g/mol

                      Hydrogen  =  1.01 g/mol

                      Oxygen  =  16.00 g/mol

Hence,

Formula mass  = (At. mass of C)₃ + (At. mass of H)₆ + (At. mass of O)

Formula mass  = (12.01)₃ + (1.01)₆ + (16.00)

Formula mass  =  36.03 + 6.06 + 16.00

Formula mass  =  58.09 g

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Iron has density 7.87 g/cm^3. if 52.4 g of iron is added to 75.0 mL of water in a graduated cylinder, to what volume reading wil
vlada-n [284]

Answer:

6.66 mL

Explanation:

The increase in the volume is due to the addition of the iron whose volume can be calculated as:

Using,

Density = Mass / Volume

Given that:

Density of Iron = 7.87 g/cm³

Mass of iron = 52.4 g

Thus, volume is:

Volume = Mass / Density = 52.4 / 7.87 cm³ = 6.66 cm³

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nikitadnepr [17]

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4Al + 3O_2 \longrightarrow 2Al_2O_3\\

… because <em>two substances are combining to make one other substance</em>.

4\stackrel{\hbox{0}}{\hbox{Al}} + 3\stackrel{\hbox{0}}{\hbox{O}}_2 \longrightarrow 2\stackrel{\hbox{+3}}{\hbox{Al}}_2\stackrel{\hbox{-2}}{\hbox{O}}_3\\

It is also a <em>reduction-oxidation reaction</em> because the <em>oxidation number of Al increases</em> from 0 to +3 and the <em>oxidation number of O</em> decreases from 0 to -2.

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3 years ago
A quantity of gas has a volume if 400.0 ml when confined under a pressure of 600.0mm Hg. What will be the new volume of the gas
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Answer:

1200 mL

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 400 mL.

Initial pressure (P1) = 600 mmHg.

Final volume (V2) =..?

Final pressure (P2) = 200 mmHg

Step 2:

Determination of the final volume i.e the new volume of the gas.

Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:

P1V1 = P2V2

600 x 400 = 200 x V2

Divide both side by 200

V2 = (600 x 400) /200

V2 = 1200 mL

Therefore, the new volume of the gas is 1200 mL.

3 0
2 years ago
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