2 years ago

Find the slope of the line passing through (3, 7) and (6, 11). Note: Use the y-y/x-x formula!

Mathematics

1 answer:

lana [24]2 years ago

6 0

Answer:

Slope of the line $m = \frac{4}{3}$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given points are ( 3,7) and (6,11)

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

$m = \frac{11-7}{6-3}$

$m = \frac{4}{3}$

Slope of the line $m = \frac{4}{3}$

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We know is a horizontal line, so, if it passes through 1,-5, it also passes through "whatever", -5, like 20, -5 or 1000000, -5, or -100000000, -5 and so on.

so, let's pick another point say -7, -5, check the picture below, and let's check about the equation that runs through it,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 1 &,& -5~) 
% (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-(-5)}{-7-1}
\\\\\\
\cfrac{-5+5}{-7-1}\implies \cfrac{0}{-8}\implies 0
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=0(x-1)
\\\\\\
y+5=0\implies y=-5$