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azamat
3 years ago
6

Help me please its urgent!

Mathematics
1 answer:
Bess [88]3 years ago
4 0

9514 1404 393

Answer:

  2

Step-by-step explanation:

The question is asking the value of f(5). Put 5 where x is and do the arithmetic.

  f(x)=\dfrac{5x-15}{5}=x-3 \qquad\text{simplified}\\\\f(5)=5-3=\boxed{2}

The range value of interest is 2.

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In a Harris poll of 514 human resource professionals, 90% said that the appearance of a job applicant is most important for a go
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Answer:

( a ) 463 " human resource professionals " believe that the appearance of a job applicant is most important for a good first impression

( b )  Percent wise the confidence interval should be from about 86.6% to 93.4%

Step-by-step explanation:

I believe these first two parts here is sufficient enough to get you started!

" In a Harris poll of 514 human resource professionals, 90% said that the appearance of a job applicant is most important for a good first impression. Part A: Among the 514 human resource professionals who were surveyed, how many of them said that the appearance of a job applicant is most important for a good first impression?

Part B: Construct a 99% confidence interval estimate of the proportion of all human resource professionals believing that the appearance of a job applicant is most important for a good first impression. "

_____

( a ) We are given that n = 514, and p = 90%. The number of human resource professionals that said that the appearance of a job applicant is most important for a good first impression, should be the following -

514 x \frac{90}{100}

= \frac{46260}{100}

= 462.6

As the count of people can't be expressed as a fraction, the solution should be about 463 " human resource professionals. "

_____

( b ) Here the confidence level is 0.99 percent. Knowing that -

1 - ∝ = 0.99,

∝ = 1 - 0.99... = 0.01

Therefore, a 99% confidence interval estimate of the proportion of all human resource professionals believing that the appearance of a job applicant is most important for a good first impression should be calculated as directed in the attachment. By that the interval ranges as such -

0.8659 < p < 0.9341

And percent wise the confidence interval should be from about 86.6% to 93.4%

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