Point v is graphed on a number line at -6...point u is 8 units away from v....notice that it doesn't say which way....so it can go either way....so we need to find 8 units away from -6 in both directions
-6 + 8 = 2
-6 - 8 = -14
so point u can be either at 2 or at -14...ur answers are A and D
Answer:
The required point is P(-7,
) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
Answer:
y=x+8 and y=3x
Step-by-step explanation:
The Given point is (4,12)
now we can substitute the point in each of the function and check wether it lies on it or not.
A. y=x+8
substitute y=12,x=4
12=4+8=12 which is true
B. y=3x
substitute y=12,x=4
12=3*4=12 which is true
C. y=2x
substitute y=12,x=4
12=2*4=8 which is not true
D. y=x+6
substitute y=12,x=4
12=4+6=10 . which is not true
Therefore option A and B are correct.
Answer:
when x = 3, x would equal 3 since x can be substituted as 3, aka chancge any xes into 3 if they give you yhat info
Step-by-step explanation:
