Sorry I don’t get this one anymore ???
Answer:
the limit does not exist
Step-by-step explanation:
As x approaches π/2 from below, tan(x) approaches +∞. A x approaches π/2 from above, tan(x) approaches -∞. These two limits are not the same, so the limit is said not to exist.
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For a limit to exist, it must be the same regardless of the direction of approach.
Answer:
3
Step-by-step explanation:
Answer:
OPtion B
Step by step explanation:
Lets plug in a random value for x.
Lets say 5 is x
-8(-5-5)=(y+1)^2
5-5 = 0
-8(0) = 0
0 = (y+1)^2
Square root of both sides
0 = y+1
subtract one from both sides
-1 = y
that means the x is 5 and the y is -1. Option B illustrates exactly that!
Answer:
y = 2/3x +6 for x< -3
y = 2/3x +1 for x> 3
Step-by-step explanation:
The graph is a line for x < -3
( - 6,2) and ( -3,4)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 4-2)/(-3 - -6) = 2/ ( -3+6) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point ( -6,2)
y -2 = 2/3(x - -6)
y -2 = 2/3(x +6)
y-2 = 2/3 x +4
y = 2/3x +6 x< -3
The graph is a line for x > 3
(3,3) and ( 6,5)
The slope is m= ( y2-y1)/(x2-x1)
m = ( 5-3)/(6-3) = 2/ (3) = 2/3
The slope is 2/3
Using point slope form
y-y1 = m(x-x1) and the point (6,5)
y -5 = 2/3(x - 6)
y-5 = 2/3 x -4
y = 2/3x +1 x> 3
