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3 years ago

Suppose you drew a diagonal in rectangle,trapezoid,parallelogram.which figures do triangles with same shape & size?

1 answer:

8 0

The same shape and size is the parallelogram because if you draw a a diagonal line through the parallelogram you would get a triangle hope this helps.

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Please help me, I’m<br> Dumb

vova2212 [387]

Answer: OPTION C

Step-by-step explanation:

To solve the exercise shown in the image attached, you need to subtract the functions f(x) and g(x).

Keeping the above on mind, you have:

$(f-g)(x)=2x^{2}+2-(x^{2}-1)$

You must distribute the negative sign and then you must add the like terms, therefore, you obtain:

$(f-g)(x)=2x^{2}+2-x^{2}+1\\(f-g)(x)=x^{2} +3$

4 0

3 years ago

Read 2 more answers

Math problem algebra

emmasim [6.3K]

My friend the answer is calculated by dividing denominator by 2 ie the answer is 1.

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3 years ago

How to solve nonlinear equations using iteration method?

nignag [31]

This is a definition and an example of it

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3 years ago

What is the equation of the line, written in slope-intercept form? Show how you determined the equation.

kondor19780726 [428]

The equation of a line is defined by: y=mx+b

Step 1: Find the slope (rise over run) so, the rise is 15.7 and the run is 6. 15.7/6=2.62

y=2.62x+b

Step 2: Find the b value (y intercept) - this is where the line goes through the y axis. In this case, it's 15.7

Step 3: add the slope and the b value together - y=2.62x+15.7

4 0

3 years ago

List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g

finlep [7]

Answer:

a) {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c) {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

{a , b } = {(a,a) (b,b) (a,b) (b,a)}

{c , d } = {(c,c) (d,d) (c,d) (d , c) }

{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}

b) {a} ,{b},{c,d} ,{e,f},{g}

{ (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c) {a,b,c,d},{e,f,g}

{(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0

3 years ago