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Anna71 [15]
3 years ago
6

Use the GUESS method to solve the problem below.

Physics
1 answer:
pochemuha3 years ago
8 0

Answer:

2.75 m

Explanation:

Given that,

Little baby bird drops the worm and sadly watches it fall to the ground below in 0.75 seconds.

We need to find how high is the nest. Let it is h. It can be calculated using second equation of motion as follows :

h=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times (0.75)^2\\\\h=2.75\ m

So, the nest is 2.75 m high.

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A racecar driver is driving her car down the drag strip at 120 m/s. What is the shortest distance in which she can brake and sto
DaniilM [7]

Answer:

1034.78 m

Explanation:

The shortest distance is the displacement of the car from initial position to final position.

Displacement of body is given using Newton's equations of motion.

Given:

Initial velocity, u = 120 m/s

Final velocity, v = 0 m/s( As the car stops in its final position)

Coefficient of static friction, \mu=0.71

Acceleration due to gravity, g=9.8\textrm{ } m/s^{2}

Now, when brakes are applied, only friction acts on the body in a direction opposite to that of its motion.

The acceleration of the car when friction acts the stopping force is given as:

a=- \mu g.

The acceleration is negative as it reduces the velocity of the motion and acts in the direction opposite to that of the motion.

Plug in 0.71 for \mu and 9.8 m/s² for g. Solve for a.

So, a=-0.71\times 9.8=-6.958\textrm{ }m/s^{2}.

Now, displacement of the car is given using the following equation of motion:

v^{2}=u^{2} +2aS

Here, S is the displacement of the racing car.

Plug in 120 m/s for u, 0 m/s for v, -6.958 m/s² for a. Solve for S. This gives,

0^{2} =(120)^{2}+2(-6.958)S\\13.916S=14400\\S=\frac{14400}{13.916}=1034.78\textrm{ m}

Therefore, the shortest distance in which she can brake and stop is 1034.78 m.

5 0
4 years ago
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Answer:

1 m/s² down

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Answer:

d = .076 m

Explanation:

The time for frog A can be calculated from  equation of motion

v_f = v_o + at

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-0.551= 0.551 + (-9.8)(t)

t = 0.112 sec

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s = v_o t + 0.5at^2

s = (1.23)(0.112) + (.5)(-9.8)(0.112)^2

d = .076 m

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How do I use a metric conversions chart
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