To solve this problem we will apply the concepts given by the principles of superposition, specifically those described by Bragg's law in constructive interference.
Mathematically this relationship is given as
![dsin\theta = n\lambda](https://tex.z-dn.net/?f=dsin%5Ctheta%20%3D%20n%5Clambda)
Where,
d = Distance between slits
= Wavelength
n = Any integer which represent the number of repetition of the spectrum
![\theta = sin^{-1} (\frac{n\lambda}{d})](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20sin%5E%7B-1%7D%20%28%5Cfrac%7Bn%5Clambda%7D%7Bd%7D%29)
Calculating the value for n, we have
n = 1
![\theta_1 = sin^{-1} (\frac{\lambda}{d})\\\theta_1 = sin^{-1} (\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_1 = 23.3\°](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%20sin%5E%7B-1%7D%20%28%5Cfrac%7B%5Clambda%7D%7Bd%7D%29%5C%5C%5Ctheta_1%20%3D%20sin%5E%7B-1%7D%20%28%5Cfrac%7B632.8%2A10%5E%7B-9%7D%7D%7B1.6%2A10%5E%7B-6%7D%7D%29%5C%5C%5Ctheta_1%20%3D%2023.3%5C%C2%B0)
n=2
![\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (2\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = 52.28\°](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%28%5Cfrac%7B2%5Clambda%7D%7Bd%7D%29%5C%5C%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%282%5Cfrac%7B632.8%2A10%5E%7B-9%7D%7D%7B1.6%2A10%5E%7B-6%7D%7D%29%5C%5C%5Ctheta_2%20%3D%2052.28%5C%C2%B0)
n =3
![\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (3\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = \text{not possible}](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%28%5Cfrac%7B2%5Clambda%7D%7Bd%7D%29%5C%5C%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%283%5Cfrac%7B632.8%2A10%5E%7B-9%7D%7D%7B1.6%2A10%5E%7B-6%7D%7D%29%5C%5C%5Ctheta_2%20%3D%20%5Ctext%7Bnot%20possible%7D)
Therefore the intensity of light be maximum for angles 23.3° and 52.28°
Answer:
the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates is 57.6 m/s
Explanation:
Given information:
diameter of the disc, d = 11 cm, r = 5.5 cm = 0.055 m
angular speed ω = 10000 rev/min = (10000 rev/min)(2π rad/rev)(1/60 min/s)
= 1000π/3 rad/s
to calculate the maximum angular speed we can use the following formula
ω = v/r
v = ωr
= (1000π/3)(0.055)
= 57.6 m/s
Answer:
Step 1: We make the assumption that 125 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$.
Step 3: From step 1, it follows that $100\%=125$.
Step 4: In the same vein, $x\%=125$.
Step 5: This gives us a pair of simple equations:
$100\%=125(1)$.
Explanation:
D.) Vertical relationships involve unequal status, while horizontal relationships represent equal status.
HOPE THIS HELPS!
Question
What was the initial momentum of the bullet before collision?
Answer:
10 Kg.m/s
Explanation:
Momentum is a product of velocity of an object in m/s and its mass in kgs hence numerically expressed as p=mv where p is momentum, v is velocity and m is mass. Substituting m for 0.2 kg and v for 50 m/s then p=0.2*50=10 kg.m/s