Question

A flat, circular loop has 22 turns. The radius of the loop is 13.5 cm and the current through the wire is 0.52 A. Determine the magnitude of the magnetic field at the center of the loop (in T).

Answer 1

Answer:

B = 5.32 x 10⁻⁵ T

Explanation:

given,

number of turn in the loop(N) = 22

radius of loop(R) = 13.5 cm = 0.135 m

current in the wire(I) = 0.52 A

μ₀ = 4 π x 10⁻⁷ H/m

magnitude of magnetic field (B)= ?

$B = \dfrac{\mu_0 N I}{2R}\ \hat{R}$

$B = \dfrac{4\pi \times 10^{-7}\times 22 \times 0.52}{2\times 0.135}$

$B = \dfrac{1.4375\times 10^{-5}}{0.27}$

$B = \dfrac{1.4375\times 10^{-5}}{0.27}$

B = 5.32 x 10⁻⁵ T

The magnitude of magnetic field at the center of loop is equal to B = 5.32 x 10⁻⁵ T