A clock is positioned on an auditorium wall with its center 9 ft above the floor. The second hand on the clock is 10 inches long
2 answers:
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Let's start by assuming Armando's house is between Joey's and the park.
Let
be the distance Joey walked to Armando's house.
<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.
</span>
That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)
Let
be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like
Let's get rid of the plus/minuses. Squaring,
For us, that's a quadratic equation for
I'll skip right to the solutions,
We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.
Let
<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.
</span>
That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)
Let
Let's get rid of the plus/minuses. Squaring,
For us, that's a quadratic equation for
I'll skip right to the solutions,
We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.