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AlladinOne [14]
3 years ago
10

which of the following types of data organizers is best able to give a quick view of the relationship between parts of a data se

t and the whole data set?
Mathematics
2 answers:
otez555 [7]3 years ago
6 0

Answer:

circle graphs would be the answer to the question

Step-by-step explanation:

ahrayia [7]3 years ago
3 0

Answer: Circle graphs

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What is the equation, in point-slope form, of the line that has a slope of 6 and passes through the point (–1, –8)? a. y+8 = 6 (
Stolb23 [73]

Answer:

y + 8 = 6(x + 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 6 and (a, b) = (- 1, - 8), hence

y - (- 8) = 6(x - (- 1)), that is

y + 8 = 6(x + 1)

8 0
3 years ago
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Select the two names that could be used to describe the figure.
OleMash [197]

i hope it helps mark me brainliest

Step-by-step explanation:

it is Parallelogram

8 0
3 years ago
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Please help me! i need some to explain the equation for this.
topjm [15]

Answer:

  (b)  21.4

Step-by-step explanation:

There are a couple of interesting relations regarding chords and secants and tangents of a circle. With the right point of view, they can be viewed as variations of the same relation, possibly making them easier to remember.

When chords cross inside a circle (as here), each divides the other into two parts. The product of the lengths of the two parts of one chord is the same as the product of the lengths of the two parts of the other chord.

Here, that means ...

  7x = 10·15

  x = 150/7 = 21 3/7 ≈ 21.4

_____

<em>Additional comment</em>

A secant is a line that intersects a circle in two places. (A tangent is a special case of secant where the two points of intersection are the same point.) When two secants meet outside the circle, there is a special relation between the lengths of the various line segments.

Consider the line segment from the point where the secants meet each other to the far intersection point with the circle. The product of that length and the length to the near intersection point with the circle is the same for both secants.

Here's the viewpoint that merges these two relations:

<em>The product of the lengths from the point of intersection of the lines with each other to the two points of intersection with the circle is the same for each line</em>.

(Note that when the "secant" is a tangent, that product is the square of the distance from the tangent point to the point of intersection with the other line--the distance to the circle multiplied by itself.)

6 0
2 years ago
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Swati is substituting t=5 and t=9 to determine if the two expressions are equivalent.
horrorfan [7]

Answer:

No the two expressions are not equivalent.

Step-by-step explanation:

the given two expressions t=5 and t=9 are not equivalent because t being a variable cant take two numbers at a same time.however if they are placed in given two expressions of 't' such that that they give equal value when the first expression gives a value 'a' at t=5 while the other expression gives a value 'a' at t=9 then those two expressions will be equal.


4 0
3 years ago
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Solve for u.<br> U/-1 +-4=-1<br> U =
kherson [118]

Answer:

U = -3

Step-by-step explanation:

U/-1 +-4=-1

Add 4 to each side

U/-1 +-4+4=-1+4

U / -1 = 3

Multiply each side by -1

U / -1  * -1 = 3* -1

U = -3

3 0
3 years ago
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