All categories

3 years ago

Help...........................plz

Mathematics

2 answers:

denis-greek [22]3 years ago

8 0

Answer:

something called a calculator but if u want explanation here it is

Step-by-step explanation:

2 1/2 can also be represented as 5/2 and when we open the parenthesees we get 5/2 (divided by) -10. we recipricol the -10 into -1/10 and then u multiply 5/2 and -1/10 which equeals -1/4

Diano4ka-milaya [45]3 years ago

4 0

Answer: (-1/4)

Step-by-step explanation:

This divides to -1/4

You might be interested in

Please help I will give brainliest if its correct :) Question is in picture

Nonamiya [84]

Answer:

2.5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write the slope-intercept form of the equation of each line. identify the slopes y-intercept.

MrRa [10]

Answer:

Step-by-step explanation:

1) y intercept is 0

2) y intercept is 1

3) y intercept is -4

4) y intercept is 4

5) y intercept is 5

6) y intercept is 0

7) y intercept is 5

8) y intercept is 4

4 0

3 years ago

Read 2 more answers

Which congruence criteria can be used directly from the information about triangles HIJ and MNO to prove IJ¯¯¯¯¯¯≅MN¯¯¯¯¯¯¯¯¯¯ b

skelet666 [1.2K]

Answer: $\overline{IJ}\cong \overline{MN}$

Step-by-step explanation:

Given: In triangle HIJ and triangle MNO we have

$\overline{HI}\cong \overline{NO}, \angle{I}\cong \angle{N} ,\angle{H}\cong \angle{O}$

here, HI and NN are the included side between ∠I & ∠H and ∠N and ∠O.

So , by ASA congruence rule,

ΔHIJ ≅ ΔMNO

So by CPCTC (corresponding parts of the congruent triangles are congruent)

$\overline{IJ}\cong \overline{MN}$

7 0

2 years ago

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

svp [43]

Answer:

5sqrt(5) = q

-5sqrt(5) = q

Step-by-step explanation:

f(q) = q^2 -125

To find the roots set the equation equal to zero

0 = q^2 -125

Add 125 to each side

125 = q^2 -125+125

125 = q^2

Take the square root of each side

±sqrt(125) = sqrt(q^2)

±sqrt( 5*25) = q

±sqrt( 25)* sqrt(5) = q

±5* sqrt(5) = q

±5sqrt(5) = q

7 0

2 years ago

Read 2 more answers

Evaluate this indefinite integral (world)joy^world-1d(joy)

Sidana [21]

Answer:

The answer is $joy^{world} + C$

Step-by-step explanation:

Given the indefinite integral $\int (world)joy^{world-1}d(joy)$

Let world → a

joy → x

Therefore, the integral becomes $\int ax^{a-1}dx$

= $a\frac{x^{a-1+1} }{a-1+1} + C$

= $x^{a} + C$

Replacing, a → world

x → joy

Hence, $\int (world)joy^{world-1}d(joy)$ = $joy^{world} + C$

8 0

3 years ago

Read 2 more answers