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2 years ago

I made a quizzes its for funnnnnnnnnnnnnnnnn. joinmyquiz .com code: 346778

Mathematics

2 answers:

seropon [69]2 years ago

8 0

Answer: ill try it -3-

Step-by-step explanation:

Snowcat [4.5K]2 years ago

5 0

Answer:

I’m taking a chance ’cause I like you a lot

So, I’ll give it a shot, give it all that I got

La de da de da

La de da de de

Suddenly, you call my name, and I lose my brain

And I float up to the moon

La de da de de

La de da de da

Step-by-step explanation:

You might be interested in

On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the

Daniel [21]

Answer:

hello your question is incomplete attached below is the complete question

answer :

H0 : u = 21.62 ( Null hypothesis )

H1 : u = 21.62 ( alternative hypothesis )

Step-by-step explanation:

Formulating hypothesis that can be used to determine whether the population mean rate at 5 CCF of residential water discharged by U.S public utilities differs from $21.62

H0 : u = 21.62 ( Null hypothesis )

H1 : u = 21.62 ( alternative hypothesis )

3 0

2 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

2 years ago

Evaluate 6 - 2(-1) + | -5 | =

tester [92]

Answer:

Step-by-step explanation:

The product of two negative numbers is positive. The absolute value of a number is its magnitude written with a positive sign.

6 -2(-1) +|-5|

= 6 + 2 + 5

= 13

8 0

2 years ago

In the following figure, the value of x is...

coldgirl [10]

Answer:

8.3

Step-by-step explanation:

4 0

2 years ago

Paul has 2/3 as many postcards as shawn . the number of postcards shawn has is 3/5 of the number of postcards tim has. if the th

kakasveta [241]

P = ( 2 / 3 )s;
s = ( 3 / 5 )t ;
p + s + t = 280 ;
Then, p =( 2 / 3 )( 3 / 5 )t ;
p = ( 2 / 5 )t;
We solve the equation : ( 2 / 5 )t + ( 3 / 5 )t + t = 280 ;
( 2 / 5 )t + ( 3 / 5 )t + ( 5 / 5 )t = ( 1400 / 5 )t;
10t = 1400 ;
t = 1400 ÷ 10 ;
t = 140 postcards has Tim;
p = ( 2 / 5 ) × 140 = 56 postcards has Paul;
s = ( 3 / 5 ) × 140 = 84 postcards has Shawn ;

6 0

3 years ago