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GaryK [48]
3 years ago
9

Draw the line of reflection that reflects ABC onto AA'B'C'.

Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

Line of reflection → x = 1

Step-by-step explanation:

Coordinates of B → (3, 2)

Coordinates of B' → (-1, 2)

If point B is reflected across a vertical line x = a, both the points B and B' will be equidistant from the line of reflection.

Coordinates of the midpoint of the segment joining B and B'

= (\frac{x_+x_2}{2},\frac{y_1+y_2}{2})

= (\frac{3-1}{2},\frac{2+2}{2})

= (1, 2)

Line of reflection will pass through this midpoint (1, 2)

Therefore, equation of the line of reflection will be,

x = 1

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Answer:

Below.

Step-by-step explanation:

x^6 . x . x^3

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= x^(6+1+3)

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What is the value of the expression below?<br><br> 1 3/4 divided by 1/2 minus (1 1/2)^3
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Answer:

1/8

Step-by-step explanation:

Simplify the following:

(1 + 3/4)/(1/2) - (1/2 + 1)^3

Hint: | Write (1 + 3/4)/(1/2) as a single fraction.

Multiply the numerator of (1 + 3/4)/(1/2) by the reciprocal of the denominator. (1 + 3/4)/(1/2) = ((1 + 3/4)×2)/1:

(3/4 + 1) 2 - (1/2 + 1)^3

Hint: | Put the fractions in 1 + 1/2 over a common denominator.

Put 1 + 1/2 over the common denominator 2. 1 + 1/2 = 2/2 + 1/2:

(1 + 3/4) 2 - (2/2 + 1/2)^3

Hint: | Add the fractions over a common denominator to a single fraction.

2/2 + 1/2 = (2 + 1)/2:

(1 + 3/4) 2 - ((2 + 1)/2)^3

Hint: | Evaluate 2 + 1.

2 + 1 = 3:

(1 + 3/4) 2 - (3/2)^3

Hint: | Put the fractions in 1 + 3/4 over a common denominator.

Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:

4/4 + 3/4 2 - (3/2)^3

Hint: | Add the fractions over a common denominator to a single fraction.

4/4 + 3/4 = (4 + 3)/4:

(4 + 3)/4×2 - (3/2)^3

Hint: | Evaluate 4 + 3.

4 + 3 = 7:

7/4×2 - (3/2)^3

Hint: | Express 7/4×2 as a single fraction.

7/4×2 = (7×2)/4:

(7×2)/4 - (3/2)^3

Hint: | In (7×2)/4, divide 4 in the denominator by 2 in the numerator.

2/4 = 2/(2×2) = 1/2:

7/2 - (3/2)^3

Hint: | Simplify (3/2)^3 using the rule (p/q)^n = p^n/q^n.

(3/2)^3 = 3^3/2^3:

7/2 - 3^3/2^3

Hint: | In order to evaluate 3^3 express 3^3 as 3×3^2.

3^3 = 3×3^2:

7/2 - (3×3^2)/2^3

Hint: | In order to evaluate 2^3 express 2^3 as 2×2^2.

2^3 = 2×2^2:

7/2 - (3×3^2)/(2×2^2)

Hint: | Evaluate 2^2.

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7/2 - (3×3^2)/(2×4)

Hint: | Evaluate 3^2.

3^2 = 9:

7/2 - (3×9)/(2×4)

Hint: | Multiply 2 and 4 together.

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7/2 - (3×9)/8

Hint: | Multiply 3 and 9 together.

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7/2 - 27/8

Hint: | Put the fractions in 7/2 - 27/8 over a common denominator.

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(4×7)/8 - 27/8

Hint: | Multiply 4 and 7 together.

4×7 = 28:

28/8 - 27/8

Hint: | Subtract the fractions over a common denominator to a single fraction.

28/8 - 27/8 = (28 - 27)/8:

(28 - 27)/8

Hint: | Subtract 27 from 28.

| 2 | 8

- | 2 | 7

| 0 | 1:

Answer: 1/8

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