A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.
Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622
b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months
Answer:
FG = 9.7ft
Step-by-step explanation:
Find the diagram in the attachment.
The diagram is a right angled triangle since one of its angle is 90°
Using SOH CAH TOA to calculate the length FG which is the hypotenuse.
According to SOH
Sin∠G = Opposite/Hypotenuse
To get the ∠G,
∠F+∠H+∠G = 180°
18°+90°+∠G = 180°
∠G = 180°-108°
∠G = 72°
Sin72° = 9.2/FG
FG = 9.2/sin72°
FG = 9.67feet
FG = 9.7ft (to the nearest tenth of a foot)
A mile is 5280 feet so you do 5 times 5280 to get 26400.
Kilobyte = 2^10 bytes
gigabyte = 2^30 bytes
terabyte is the product of a kilobyte and a gigabyte....so we multiply
2^10 * 2^30 = 2^(10 + 30) = 2^40 <== a terabyte
** exponent rule : a^b * a^c = a^(b + c)
So we need to cover 5.5% into a decimal.
0.055 = 5.5%
The house value is 120,000.
So
(1.055x) * (120,000)=
So
f(x)=1.055x * 120,000