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icang [17]
3 years ago
5

One shape is approaching a poor from the east traveling west at 15 mph and its presently 3 miles east east of the port I second

ship is already left the poor traveling to the north at 10 mph and is presently 4 miles north of the port at this instant what is the rate of change of distance between the two ships are they going to close your more for their apart
Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

DL/dt = 17 mph

Step-by-step explanation:

The ships and the port shape a right triangle

Ship  going west ( x-direction)   is traveling at 15 mph

Ship going north  (y-direction) is traveling at 10 mph

The distance L between ships is:

L²  = x² + y²

Tacking derivatives on both sides of the equation with respect to time

we get

2*L*DL/dt = 2*x*Dx/dt  + 2*y*Dy/dt    (1)

In that equation we know:

Dx/dt  = 15 mph

Dy/dt  = 10 mph

At the moment  ship traveling from the east is at 3 miles from the port

then x = 3 m  and the other ship is at 4 miles north

then by Pythagoras theorem

L = √ 3² + 4²    L = 5

By substitution in equation 1

2*5*DL/dt  = 2*3*15 + 2*4*10

10* DL/dt  =  90  +  80

DL/dt = 170 / 10

DL/dt = 17 mph

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jolli1 [7]

A relation is a function if it has only One y-value for each x-value. Functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for  f(x)=4x²+2x-6

<h3>What is a function?</h3>

A relation is a function if it has only One y-value for each x-value.

The given function is

f(x)=2x²-4x+2

Put x=2/3

f(2/3)=2(2/3)²-4(2/3)+2

=2(4/9)-8/3+2

=8/9-8/3+2

=(8-24+18)/9

f(2/3)=2/9

Now f(x)=4x²+2x-6

Put x=1/4

f(1/4)=4(1/4)²+2(1/4)-6

=4/16+2/4-6

=1/4+1/2-6

= 1+2-24/4

f(1/4)==-21/4

Hence functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for  f(x)=4x²+2x-6

To learn more on Functions click:

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3 0
1 year ago
PLs help lots of points
NikAS [45]

Answer:

I believe it is cube A

Step-by-step explanation:

the volume of Cube B equaled 2073.6 in for me. so it would be less than cube A

4 0
3 years ago
Read 2 more answers
The graph of F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x). If F(x) = x^2, which of
katrin [286]

The transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The options are missing.

The options are:

A. G(x) = 4x²

B. G(x) = -(1/4)x²

C. G(x) = -4x²

D. G(x) = (1/4)x²

We have an equation of a function F(x)  

F(x) = x²

The transformation F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x)

To stretch vertically if the function is multiplied by a constant value

f(x) = ax²

To flip over the x-axis if multiply by negative value.

g(x) = -ax²

From the options

G(x) = -4x²

Thus, the transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.

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6 0
2 years ago
The ellipse x^2/4 + y^2/16 = 1<br> Has a vertical axis of??<br> 8<br> 16<br> 4<br> 3
photoshop1234 [79]
I might be wrong but I say 16
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3 years ago
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PIT_PIT [208]
B is equal to 154 degrees. we know this cause half of the circle equals 180 and if you subtract a (26) from 180 you get 154
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