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3 years ago

How do erosion and deposition work together to form sand dunes?

Chemistry

2 answers:

Leona [35]3 years ago

8 0

Answer:

Erosion occurs through deflation, and sand that was picked up is deposited against an obstruction.

Explanation:

Erosion can be defined as a geological process which involves the wearing away of earth material and transportation of these material to another location by Natural agents such as wind and water. Erosion involves removal of top soil, rocks and other earth particles by action of wind, glacier and water.

Wind causes erosion by deflation. Deflation is the actual removal of grain of rocks . Generally, it s the lowering of land surface that happens as a result of removal of surface particles(sands grains) by wind. Deflation is usually prevalent in arid areas. This sand can later be picked up and deposited to form sand dunes . Sand dunes are mounds of sand formed by wind . This sands are sheltered by an obstacle. And sand dunes are prevalent in desert and or along the beach. The sand dune grows as sand accumulate.

Inga [223]3 years ago

8 0

Answer: D

Explanation:

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2 years ago

Scorpion4ik [409]

Answer:

0.24M

Explanation:

The equation for the reaction is given below:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the equation above, we obtained the following information:

nA (mole of acid) = 1

nB (mole of base) = 2

Data obtained from the question include:

Va (volume of the acid) = 12mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 36mL

Cb (concentration of the base) = 0.16 M

The Ca (concentration of the acid) can be obtained as follow:

CaVa/CbVb = nA/nB

Ca x 12 / 0.16 x 36 = 1 /2

Cross multiply to express in linear form as shown below:

Ca x 12 x 2 = 0.16 x 36

Divide both side by 12 x 2

Ca = 0.16 x 36/ 12 x 2

Ca = 0.24M

Therefore, the concentration of the acid is 0.24M

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3 years ago