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satela [25.4K]
3 years ago
13

The main sugar that is used as a reactant in cellular respiration is called

Chemistry
2 answers:
vekshin13 years ago
6 0

Answer:

I believe that the answer is glucose?

Explanation:

if not, tell me the answer choices and i will help u from there

Llana [10]3 years ago
3 0
Answer:

Glucose


Explanation:

The two cellular processes illustrated by the test tubes are cellular respiration and photosynthesis. During cellular respiration, the reactants—glucose (sugar) and oxygen—combine together to form new products: carbon dioxide molecules and water molecules.
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How do many indoor environments generally compare to outdoor environments in terms of pollution? Indoor environments are much le
brilliants [131]
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4 0
3 years ago
Which period is older than the Triassic period? Cambrian Cretaceous Jurassic Paleogene.
scoundrel [369]

The Triassic period is one of the geological periods and is the shortest of the Mesozoic era. Cambrian is the older era than the Triassic period.

<h3>What is Cambrian and triassic period?</h3>

The Triassic period existed 250 -200 million years ago and started after the vastest and most extreme devastation ever. It is the 1st period of the Mesozoic and is known for the movement of the Dinosaurs on the land, flying pterosaurs and swimming plesiosaurs and ichthyosaurs.

The Cambrian is the period of the Paleozoic era and is the most important period because of the appearance of many animals. In this period, the temperature raised on the planet and the ice sheets melted at a very dangerous rate leading to mass devastation.

Therefore, option A. <u>Cambrian</u> is older than the Triassic period.

Learn more about Cambrian and Triassic periods here:

brainly.com/question/11417834

6 0
2 years ago
A solution of salt and water is 33.0% salt by mass and has a density of 1.50 g/ml. what mass of the salt in grams is in 5.00l of
meriva
To answer this item, we solve first for the mass of the solution by multiplying the density by the volume. That is,

      m = (density)(volume)

Substituting the known values,
    m = (1.50 g/mL)(5L)(1000 mL/1L)
      m = 7500 grams

To determine the mass of the salt in the solution, multiply the calculated mass of the solution by the decimal equivalent of the percent salt in the solution.

      m of salt = (7500 g)(0.33)
      m of salt = 2475 grams

<em>Answer: 2475 grams</em>
6 0
3 years ago
Calculate the number of moles of solute present in 185.0 mL of a 1.50 mol/L solution of HCl.
____ [38]

Answer:

0.278 mol HCl

Explanation:

We currently have 185.0 mL of a 1.50 mol/L solution of HCl. We want to find the number of moles there are.

Based on the given information, our volume is 185.0 mL and our molarity is 1.50. Because molarity is defined as moles / Litre, we can easily find the moles given volume by multiplying molarity by volume.

First, though, we must convert millilitres to litres. There are 1000 mL in 1 L, so divide 185.0 by 1000:

185.0 / 1000 = 0.185 L

Now, multiply 0.185  by 1.50:

0.185 L * 1.50 mol/L = 0.278 mol HCl

Thus the answer is 0.278 mol HCl.

<em>~ an aesthetics lover</em>

4 0
3 years ago
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