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satela [25.4K]
2 years ago
13

The main sugar that is used as a reactant in cellular respiration is called

Chemistry
2 answers:
vekshin12 years ago
6 0

Answer:

I believe that the answer is glucose?

Explanation:

if not, tell me the answer choices and i will help u from there

Llana [10]2 years ago
3 0
Answer:

Glucose


Explanation:

The two cellular processes illustrated by the test tubes are cellular respiration and photosynthesis. During cellular respiration, the reactants—glucose (sugar) and oxygen—combine together to form new products: carbon dioxide molecules and water molecules.
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Astronomers often scan the sky using devices called radio
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Explanation:

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What does a neutralization reaction produce?
algol13

Answer:

hope this help....

Explanation:

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What is the ratio of carbon, hydrogen, and oxygen in most carbohydrates?
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Able 1 Cell Type Operating Cell Potential for Commercial Batteries, E (V) Lithium-iodine Zinc-mercury +2.80 +1.35 Table 2 Standa
IrinaK [193]

Answer:

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.  ( B )

During the initial cell operation, the oxidation of iodine is  thermodynamically favorable but the oxidation of mercury is not. ( C )

Explanation:

<u>The major Differences between The Zinc mercury cell and Lithium-iodine cell are :</u>

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.   and

During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.

Given the relationship below,

Δ G = -nFE

E = emf of cell ,  G = free energy.

This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy  also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable

8 0
2 years ago
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