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Alexxandr [17]
3 years ago
7

Please help

Chemistry
1 answer:
photoshop1234 [79]3 years ago
4 0

Answer:

Atomic radius is directly proportional to Metallic reactivity in group 2.

Explanation:

Atomic radius is directly proportional to Metallic reactivity in group 2.

As we move down the group in group 2 which is called as the alkaline earth metals, the atomic number increases due to which the subshell increases. And the outermost shell's electron are less tightly held to the nucleus of the atom. Since the electrons are loosely held that means they can easily participate in reactions and that what makes it reactive down the 2nd group. Therefore alkaline earth metals with higher atomic number are more chemically reactive.

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Make a consistent control of weight diminishing valves giving gas.

No smoking zone.
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3 years ago
Worldwide, the single most important chemical weathering agent is ________. worldwide, the single most important chemical weathe
Juliette [100K]
The single most important chemical weathering agent is Carbon dioxide.
Weathering refers to the process that change the physical and chemical character of rock at or near the surface. Weathering has a dramatic impact on the composition of Earth's atmosphere. Chemical weathering removes carbon dioxide from the atmosphere, allowing it to be transformed into limestone and stored in the crust. Without chemical weathering, the elevated levels of carbon dioxide in the atmosphere would have long made Earth too hot to sustain life. 
4 0
2 years ago
What is not within the scope of chemistry
ankoles [38]

hello!

your answer will be

The origin of the matter does not usually fall into chemistry

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5 0
3 years ago
During laparoscopic surgery , carbon dioxide gas is used to expand the abdomen to help create a larger working space. If 4.80 L
Studentka2010 [4]

Answer:

5.37 L

Explanation:

To solve this problem we need to use the PV=nRT equation.

First we <u>calculate the amount of CO₂</u>, using the initial given conditions for P, V and T:

  • P = 785 mmHg ⇒ 785/760 = 1.03 atm
  • V = 4.80 L
  • T = 18 °C ⇒ 18 + 273.16 = 291.16 K

1.03 atm * 4.80 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 291.16 K

We <u>solve for n</u>:

  • n = 0.207 mol

Then we use that value of n for another PV=nRT equation, where T=37 °C (310.16K) and P = 745 mmHg (0.98 atm).

  • 0.98 atm * V = 0.207 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 310.16 K

And we <u>solve for V</u>:

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7 0
3 years ago
A sample originally contained 1.28 g of a radioisotope. It now contains 1.12 g of its daughter isotope.
dexar [7]
The answer is 3.

<span>The relation between number of half-lives (n) and decimal amount remaining (x) can be expressed as:

</span>(1/2) ^{n} =x

We need to calculate n, but we need x to do that. To calculate what p<span>ercentage of a radioactive species would be found as daughter material, we must calculate what amount remained:
1.28 -</span> 1.12 = 0.16

If 1.28 is 100%, how much percent is 0.16:
1.28 : 100% = 0.16 : x
x = 12.5% 
Presented as decimal amount:
x = 0.125


Now, let's implement this in the equation: 

<span>(1/2) ^{n} =0.125
</span>
Because of the exponent, we will log both sides of the equation:
n * log(1/2) = log(0.125)
n = \frac{log(0.125)}{log(1/2)}
<span>n = \frac{log(0.125)}{log(0.5)}
</span>n= \frac{-0.903}{-0.301}
n = 3

Therefore, 3 half-lives have passed <span> since the sample originally formed.</span>
4 0
3 years ago
Read 2 more answers
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