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3 years ago

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Chemistry

1 answer:

photoshop1234 [79]3 years ago

4 0

Answer:

Atomic radius is directly proportional to Metallic reactivity in group 2.

Explanation:

Atomic radius is directly proportional to Metallic reactivity in group 2.

As we move down the group in group 2 which is called as the alkaline earth metals, the atomic number increases due to which the subshell increases. And the outermost shell's electron are less tightly held to the nucleus of the atom. Since the electrons are loosely held that means they can easily participate in reactions and that what makes it reactive down the 2nd group. Therefore alkaline earth metals with higher atomic number are more chemically reactive.

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Chlorofluorocarbons (CFCs) are no longer used as refrigerants because they destroy the ozone layer. Trichlorofluoromethane (CCl₃

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The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

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What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL sa

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The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 1.25 mL

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of stomach acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.1M\\V_2=25mL$

Putting values in above equation, we get:

$1\times 2\times V_1=1\times 0.1\times 25\\\\V_1=\frac{1\times 0.1\times 25}{1\times 2}=1.25mL$

Hence, the volume of HCl neutralized is 1.25 mL

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3 years ago