Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.
From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.
From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.
Thus from 1.8 moles of C we can obtain 
×1.8 = 0.3 moles of the propane can be prepared.
Thus the amount of propane produced in this reaction is determined.
No this is incorrect. We do not want the greenhouse affect
Una mezcla homogenea es una mezcla solida, liquida o gaseosa que tiene las mismas proporciones de sus componentes en cualquier muestra dada. A la inversa, una mezcla heterogenea tiene componentes cuyas proporciones varian a lo largo de la muestra. "Homogeneo" y "heterogeneo" no son terminos absolutos sino que dependen del contexto y del tamano de la muestra. En quimica, una suspension homogenea de material significa que cuando se divide el volumen a la mitad, la misma cantidad de material se suspende en ambas mitades de la sustancia; sin embargo, podria ser posible ver las particulas bajo un microscopio. Un ejemplo de una mezcla homogenea es el aire.
Answer:
Percent yield = 57%
Explanation:
Given data:
Mass of nitrogen = 15.0 g
Mass of hydrogen = 15.0 g
Mass of ammonia produced = 10.5 g
Percent yield = ?
Solution:
Chemical equation:
N₂+ 3H₂ → 2NH₃
Number of moles of hydrogen:
Number of moles = mass/molar mass
Number of moles = 15.0 g/ 2 g/mol
Number of moles = 7.5 mol
Number of moles of nitrogen:
Number of moles = mass/molar mass
Number of moles = 15.0 g/ 28 g/mol
Number of moles = 0.54 mol
Now we will compare the moles of ammonia with nitrogen and hydrogen from balance chemical equation.
N₂ : NH₃
1 : 2
0.54 : 2×0.54 = 1.08
H₂ : NH₃
3 : 2
7.5 : 2/3×7.5= 5 mol
Theoretical yield of ammonia:
Mass = number of moles × molar mass
Mass = 1.08 × 17 g/mol
Mass = 18.36 g
Percent yield:
Percent yield = (actual yield / theoretical yield) ×100
Percent yield = (10.5 g/ 18.36 g) ×100
Percent yield = 0.57 ×100
Percent yield = 57%
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