When we have this equation:
CO(g) + Cl2(g) ↔ COCl2(g)
intial 0.147 0.175 0
change -X -X +X
final (0.147-X) (0.175-X) X
so from the ICE table, we substitute in Kc formula :(when we have Kc = 255)
Kc = [COCl2]/[CO][Cl2]
255= X / (0.147-X)(0.175-X)
255 = X / (X^2 - 0.322 X + 0.025725)
X = 0.13
∴[CO] = 0.147 - X = 0.147 - 0.13
= 0.017 m
Answer:
The answer is 2
Explanation:
I got it right in the k12 test :)
teehee
Answer:
V1 / T1 = V2 / T2
V₁ = 420 mL
T₁ = 210 K
V₂ = ?
T₂ = 250 K
420 / 210 = V2 / 250
V2 = (420 / 210) x 250 = 500 mL
Explanation:
Answer:
1. Polar
2 nonpolar
3. Nitrogen or oxygen
4.carbon
5.Repelled by and attracted to
Answer:
[O₂(g)] = 0.0037M
Explanation:
2SO₂(g) + O₂(g) => 2SO₃(g)
Conc: [SO₂(g)] [O₂(g)] [SO₃(g)] and [SO₂(g)] = [SO₃(g)]
Kc = [SO₃(g)]²/[O₂(g)][SO₂(g)]² => Kc = 1/[O₂(g)] = 270 if [SO₂(g)] = [SO₃(g)]
∴ [O₂(g)] = (1/270)M = 0.0037M
