Answer:
Mg²⁺(aq) + SO₄²⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + 2OH⁻(s) + 2Na⁺(aq) + SO₄²⁻(aq)
Explanation:
The complete ionic equation is the chemical equation where the chemical species in the aqueous phase (aq) are written as ions.
In the reaction:
MgSO₄(aq) + 2NaOH(aq) → Mg(OH)₂(s) + Na₂SO₄(aq)
MgSO₄ dissociates in Mg²⁺ and SO₄²⁻, NaOH in Na⁺ and OH⁻, Mg(OH)₂ doesn't dissociate because is as solid and NaSO₄ dissociates in Na⁺ and SO₄²⁻ ions.
That means the complete ionic equation is:
<h3>Mg²⁺(aq) + SO₄²⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + 2OH⁻(s) + 2Na⁺(aq) + SO₄²⁻(aq)</h3>
Answer:
the answer would be C
i took this from a quizlet
hopes this helps<3
Answer: N-N: 145 pm and 167 KJ/mol
N=N: 125 pm, 418 KJ/mol
And N2: 110 pm , 942 KJ/mol
Explanation: Bond length is inversily proportional to bond energy.
Greater the bond length , smaller the bond energy and vice-versa.
For the first question, salt is soluble while sand is insoluble or not dissolvable in water. The salt should have vanished or melted, but the sand stayed noticeable or visible, making a dark brown solution probably with some sand particles caught on the walls of the container when the boiling water was put in to the mixture of salt and sand. The solubility of a chemical can be disturbed by temperature, and in the case of salt in water, the hot temperature of the boiling water enhanced the salt's capability to melt in it.
For the second question, the melted or dissolved salt should have easily made its way through the filter paper and into the second container, while the undissolved and muddy sand particles is caught on the filter paper. The size of the pores of the filter paper didn’t change. On the contrary, the size of the salt became smaller because it has been dissolved which is also the reason why it was able to go through the filter paper, while the size of the sand may have doubled or even tripled which made it harder to pass through.
It’s Tetracarbon dioxide :)
