Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
X is one angle
X+78 is the second angle
Add them together
2x+78=90
Subtract 78 from both sides
2x=12
X=6
One angle is 6 the other angle is 84
The absolute value of I9I is 9 and -9 but I would put 9 first if you can only pick one
Answer:
the square root of 169 is 13 then ×2
26
I hope I am correct mate
enjoy your day
#Captainpower
Answer:
q12 is 8
q13 is 81
Step-by-step explanation:
100*6 =600 / 75 = 8
90*72 = 6480 / 80 = 81
