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3 years ago

Find the measure of the missing angle using the exterior angle sum theorm

Mathematics

1 answer:

Alina [70]3 years ago

7 0

Step-by-step explanation:

the sum of angels of a triangle is 180°

130+ ? + (180-160) = 180

130+ ? +20= 180

150+ ? = 180

? = 30°

the missing angle is 30°

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A coral reef grows

const2013 [10]

It grows 1.68m because 0.14m times 12

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3 years ago

Read 2 more answers

2(8-12x)+8x=-25x+52 show your work pls I am so confused on this.

Allisa [31]

Answer:

x=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Add 25x to both sides.

Step 3: Subtract 16 from both sides.

Step 4: Divide both sides by 9.

8 0

3 years ago

Express 2x^2+3x/(2x+3)(x-2) - 6/x^2-x-2 As a single fraction in its simplest form.

Dmitry [639]

Answer:

(x + 3)/(x + 1) .

Step-by-step explanation:

2x^2 + 3x/(2x + 3)(x - 2) - 6 /x^2 - x - 2

= 2x^2 + 3x/(2x + 3)(x - 2) - 6 / (x - 2)(x + 1)

The LCM is (2x + 3)(x - 2)(x + 1) so we have

(2x^2 + 3x)(x + 1) - 6(2x + 3) x( 2x + 3)(x + 1) - 6(2x + 3)

--------------------------------------- = ------------------------------------

(2x + 3)(x - 2)(x + 1) (2x + 3)(x - 2)(x + 1)

(2x + 3)(x(x + 1) - 6) (2x + 3)(x - 2)(x + 3)

= ---------------------------- = --------------------------- = (x + 3)/(x + 1)

(2x + 3)(x - 2)(x + 1) (2x + 3)(x - 2)(x + 1)

7 0

3 years ago

Negative ten is no less than two times a number plus fourteen

creativ13 [48]

All you do is change signs write 2x minus 14 equals negative 10-14 equals four then you write 2x over two equals four over two then u write x equals negative two

5 0

3 years ago

I need help!

blagie [28]

Here is the solution...

1) $\sqrt[3]{135} \\$

Solution

We can rewrite $\sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}$

Here, $\sqrt[3]{27} = 3$

Now substitute the value, we get

$\sqrt[3]{135} = 3 \sqrt[3]{5}$

The answer is $3\sqrt[3]{5}$

2) $-5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}$

Here $\sqrt[3]{8} = \sqrt[3]{2^{3} } = 2\\$

Therefore, we get $-5*2\sqrt[3]{5} = -10 \sqrt[3]{5}$

The answer is-10 \sqrt[3]{5}[/tex]

2) $2\sqrt[3]{5} * 4\sqrt[3]{8}$

Solution

$\sqrt[3]{8} = 2$

Now plug in the above in the given expression, we get

$2\sqrt[3]{5} * 4*2 = 16\sqrt[3]{5}$ {2*4*2 = 16]

The answer is $16\sqrt[3]{5}$

8 0

3 years ago