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3 years ago

PLEASE HELP THIS IS DUE TODAYYYY

Mathematics

1 answer:

mixer [17]3 years ago

4 0

Answer:

Choice 4

Step-by-step explanation:

hope this helpss :))

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Add. Write fractions in simplest form.<br> 4-12 EVENS

Virty [35]

4. 1/3 6.-0.9 or -9/10 8. 2 1/3 10. -3.45 12.4.54 or 4 27/50

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3 years ago

Does 2.5, 6, 6.5 form a right triangle

yawa3891 [41]

Yes I think it’s s right triangle

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3 years ago

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Someone please do this for me to be the brainliest personnn I will love you forever

laila [671]

Answer:

1) 2

2) -7/6

3) -5/4

4) -1/2

5) -13/28

6) 9/7

Step-by-step explanation:

5) (-6-7)/(17-(-11))=-13/28

6) (4-(-5)/(3-(-4))=9/7

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3 years ago

Solve for n 50 points <br><br> a=p(1+r/n)^rn

Andreyy89

Answer:

$n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }$

Step-by-step explanation:

$a=p(1+\frac{r}{n} )^{nt}$

$\frac{a}{p} =(1+\frac{r}{n} )^{nt}$

$\sqrt[nt]{\frac{a}{p}} =(1+\frac{r}{n} )$

$\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )$

$n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }$

[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]

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2 years ago

When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

borishaifa [10]

Answer:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

7 0

3 years ago