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Vera_Pavlovna [14]
3 years ago
15

A differential equation that is a function of y only

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 1
ANSWER
<span>will produce a slope field with rows of parallel tangents 
</span>
EXPLANATION
A differential equation that is a function of y only does not depend on x, i.e. of the form dy/dx = f(y), where f is a function.

Therefore, the slope field will be independent of the horizontal position. This means that there will be rows where the slopes will be of the same rise/run ratio. When two slopes are the same, they are said to be parallel.
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Slav-nsk [51]

Answer:

its A im pretty sure

Step-by-step explanation:

8 0
2 years ago
When will these two lines intersect <br>C. y=-2x +3<br>y = x​
Andrej [43]

Answer:

The intersection point  of the given lines is  (1,1).

Step-by-step explanation:

Here, the given equations are:

y  =  - 2 x +  3

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Substitute y = x in  the first equation,

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or, y + 2 y = 3

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8 0
3 years ago
A company has two manufacturing plants with daily production levels of 5x + 11 items and 2x - 3 items, respectively. The first p
Brrunno [24]

Answer:

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2 years ago
N is the sum of three consecutive primes and is also the product of two 2-digit primes, what is the least possible value of N
Nookie1986 [14]

Hello from MrBillDoesMath!

Answer:   N = 143

Discussion:

This one took some trial and error! At first I listed all 2 digit primes, looked at the list, but didn't know how to proceed. So, I took the smallest 2 digit primes numbers:  11 and 13 and wondered if their product, 13*11 = 143, could be represented as the sum of  3 consecutive primes.   I went back to my list of primes,  added groups of three consecutive numbers that seemed to be in the right range to give the desired sum, and stumbled on  43, 47, and 53!

43 + 47 + 53 =  143 !


Therefore N = 143. It's the sum of 43, 47, and 53 as well as the product of 11 and 13.


Thank you,

MrB


7 0
3 years ago
What is the slope of the line represented by the equation y = y equals 4 Over 5
OLEGan [10]

\bf y= \stackrel{\stackrel{m}{\downarrow }}{\cfrac{4}{5}}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

4 0
3 years ago
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