Answer:
400; 800
Explanation:
Contribution:
Product X:
= Selling price - Variable cost
= 100 - 70
= 30,
Product Y:
= Selling price - Variable cost
= 80 - 40
= 40,
Product Z:
= Selling price - Variable cost
= 25 - 20
= 5
Machine hours required :
Product X:
= Machine time per unit × Monthly demand
= 3 × 300
= 900,
Product Y:
= Machine time per unit × Monthly demand
= 2 × 200
= 400,
Product Z:
= Machine time per unit × Monthly demand
= 1 × 500
= 500
Contribution per machine hour:
Product X = Contribution ÷ Machine time per unit
= 30 ÷ 3
= 10,
Product Y = Contribution ÷ Machine time per unit
= 40 ÷ 2
= 20,
Product Z = Contribution ÷ Machine time per unit
= 5 ÷ 1
= 5
It is highest for Y, so produce maximum amount of Y, then X and then Z
Y needs 400 hrs, we are left with 800 hours, so produce 800 hours of X.
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
Answer:
It does not
Explanation:
In this question, we are asked to evaluate if a particular transaction carried out between a customer and an inn falls within the dictates of the local consumer protection law in the state.
Firstly, we look at what the local consumer protection law of the state talks about. It explicitly stated that customers should get receipts when suppliers receive deposits from them. Thus, this make the receipt act as the first thing to have if there would be any claim under the consumer protection law for the transaction carried out in the state.
Now, looking at the particular scenario we have, the customer paid for the room, but he was not issued a receipt. This makes the case not treatable within the consumer protection law of the state as the receipt which should have been a prerequisite for further exploration is not available
First drop down box: Mission
Second drop down box: Measurement
