<span>4x² - 5x + 1 = 0
a = 4; b = - 5, c = 1
</span>Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9
<span>
x = - b </span>± √Δ / 2.a
A. Two real solutions (x' = -1 and x'' = -1/4)
Answer:
a) d²y/dx² = ½ x + y − ½
b) Relative minimum
Step-by-step explanation:
a) Take the derivative with respect to x.
dy/dx = ½ x + y − 1
d²y/dx² = ½ + dy/dx
d²y/dx² = ½ + (½ x + y − 1)
d²y/dx² = ½ x + y − ½
b) At (0, 1), the first and second derivatives are:
dy/dx = ½ (0) + (1) − 1
dy/dx = 0
d²y/dx² = ½ (0) + (1) − ½
d²y/dx² = ½
The first derivative is 0, and the second derivative is positive (concave up). Therefore, the point is a relative minimum.
Answer:
The length of TQ is 14.
Step-by-step explanation:
The length of SV and VS are the same.
4x - 1 = 15
4x = 16
x = 4
Similarly, the length of TS and TQ are the same.
3x + 2 = 3(4) + 12 = 14
Answer:
1.5
1.5%
10/0
7/20
35.1%
8.20%
8.20
Step-by-step explanation:
there u go
The answer should be 64 cars sold at the dealership
