Ask question

Ask question

All categories

Gelneren [198K]

2 years ago

6

A bag of marbles has 5 blue marbles, 3 red marbles, and 6 yellow marbles. A marble is drawn from the bag at random . How many po

ssible possible outcomes are there?
° 3
° 5
° 6
° 14
HELP ME ASAP PLZ

1 answer:

trasher [3.6K]2 years ago

5 0

The anser is 14 I guess because there are 14 marbles in total giving you 14 outcomes

You might be interested in

MT is a diameter of OE. Calculate the measure of ZMTH.

irga5000 [103]

Answer:

A. 17°

Step-by-step explanation:

Recall: measure of an inscribed angle = ½(intercepted arc)

Inscribed angle = m<MTH

Intercepted arc = arc MH = 34°

Therefore,

m<MTH = ½(Arc MH)

Substitute

m<MTH = ½(34)

m<MTH = 17°

8 0

2 years ago

Tickets to a local circus cost $5 for students and $8 for adults. A group of 9 people spent a total of $60. How many adults were

S_A_V [24]

Answer:

5

Step-by-step explanation:

You need to set up and solve a system of linear equations here.

Let s and a represent the number of students and adults respectively.

Then s + a = 9, and s = 9 - a.

Total ticket cost for the adults was ($8/adult)(a)

and for the students ($5/student)(s).

Total cost of the tickets was then ($8/adult)(a) + ($5/student)(s) = $60.

Then our system of linear equations is:

8a + 5s = 60

a + s = 9, or s = 9 - a. Substituting 9 - a for s, we get:

8a + 5(9 - a) = 60.

Then 8a + 45 - 5a = 60, or 3a = 15.

Solving for a, we get a = 5.

Solving for s using s = 9 - a, we get s = 9 - 5, or s = 4.

There were 5 adults in the group (and 4 students).

3 0

3 years ago

Antoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00.

lana66690 [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help me!!!

Vladimir79 [104]

Answer:

130

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Let u = (1, k) and v = (2, 1). Find k such that The distance between u and v is 1 u and v are orthogonal The angle between u and

SVETLANKA909090 [29]

Answer:k=1,k=-2,k= $8\pm 5\sqrt{3}$

Step-by-step explanation:

Given two vectors

$u=1\hat{i}+k\hat{j}$

$v=2\hat{i}+1\hat{j}$

$\left ( i\right )$ Distance between them is given by

$|u-v|=\sqrt{\left ( 2-1\right )^2+\left ( 1-k\right )^2}=1$

squaring both side

$1^{2}+\left ( 1-k\right )^2=1$

$k^2-2k+1=0$

$\left ( k-1\right )^2=0$

k=1

$\left ( ii\right )$

angle between u and v is 90 i.e. orthogonal

$u\dot v=0$

$\left ( 1\hat{i}+k\hat{j}\right )\dot \left ( 2\hat{i}+1\hat{j}\right )$ =0

2+k=0

k=-2

$\left ( iii\right )$

angle between u & v is $\frac{\pi }{3}$

$u\dot v=|u||v|cos\left (\frac{\pi }{3}\right )$

$|u|=\sqrt{1^2+k^2}$

$|v|=\sqrt{2^2+1^2}$

$2+k=\left ( \sqrt{1+k^2}\right )\left ( \sqrt{5}\right )cos\left ( \frac{\pi }{3}\right )$

$\left ( 4+2\right )^2=\left ( 1+k^2\right )5$

$k^2-16k-11$ =0

k= $8\pm 5\sqrt{3}$

7 0

3 years ago