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2 years ago

Solve the equation for y 9x - 3y = 12

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

8 0

3y = 9x - 12
y = 3x - 4

i am a mathematics teacher. if anything to ask please pm me

liberstina [14]2 years ago

8 0

I think its 1 for both<span />

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Margarita [4]

In words it would be: negative one point eight three eight three eight three

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3 years ago

Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif

Novay_Z [31]

Answer: Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

Step 2: Removing parenthesis

Step 3: Grouping like terms

Step 4: Combing like terms

Step 5: Writing the final expression in standard form

Step-by-step explanation: First expression : $6x^3-2x + 3$

Second expression : $-3x^3+5x^2+4x-7$ .

We need to subtract $6x^3-2x + 3$ from $-3x^3+5x^2+4x-7$ .

Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

$(-3x^3+5x^2+4x-7)+(-6x3+2x-3)$

Step 2: Removing parenthesis

$(-3x^3) +5x^2+4x + (-7) + (-6x^3) + 2x + (-3)$

Step 3: Grouping like terms

$[-3x^3) + (-6x^3)] + [4x + 2x] + [(-7) + (-3)] + [5x^2]$

Step 4: Combing like terms

$-9x^3 + 6x + (-10) + 5x^2$

Step 5: Writing the final expression in standard form

$-9x^3 + 5x^2 + 6x-10$

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3 years ago

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Factor and solve the problems in the photo ……….. pleaseeeee help i haven’t done algebra in 2 years

vladimir1956 [14]

Answer:

30. 2x²-x-1=0

or, 2x²-2x+x-1=0

or, 2x(x-1)+1(x-1)=0

or, (x-1)(2x+1)=0

so, x-1 = 0 or, x = 1

and 2x+1 = 0 or, 2x = -1 or, x = -1/2

so, x = 1 and 1/2

31. 3x²-14x=5

or, 3x²-14x-5=0

or, 3x²-15x+x-5=0

or, 3x(x-5)+1(x-5)=0

or, (x-5)(3x+1)=0

so, x-5=0 or, x=5

and 3x+1=0 or, 3x=-1 or, x=-1/3

so, x = 5 and -1/3

Answered by GAUTHMATH

5 0

3 years ago

Please I need answers Factorize x²-6x+9

miskamm [114]

Answer:

The factors of the given equation are:

$x^2-6x+9=(x-3)(x-3)=(x-3)^2$

Step-by-step explanation:

We have :

$x^2-6x+9$

Using middle term splitting theorem to factorize the expression :

$x^2-3x-3x+9$

$x(x-3)+(-3)(x-3)$

$(x-3)(x-3)$

$x^2-6x+9=(x-3)(x-3)=(x-3)^2$

The factors of the given equation are:

$x^2-6x+9=(x-3)(x-3)=(x-3)^2$

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3 years ago

{(2,2),Is this a function?

ExtremeBDS [4]

No, it is not a function because that is for any y single value.

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3 years ago

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