<span>The speed is 57.5 m/s and the parachutist will fall 1150 m in 20 seconds.
Explanation<span>:
We start out with the ratio 207 km/1 hr.
We know that 1 km = 1000 m; this means 207 km = 207*1000 = 207000 m. This gives us 207000 m/1 hr.
We know that 1 hr = 60 minutes, so we have 207000 m/60 min.
We also know that 1 min = 60 seconds, so 60 min = 60*60 = 3600 sec; this gives us 207000 m/3600 sec.
Dividing this, we get 57.5 m/s.
In 20 seconds, the parachutist will fall 57.5(20) = 1150 m.</span></span>
Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr
This is a link that I gave to my little sister that helped her understand what interquartile range is. It has an example as well! I hope this helps!
Basically, you have two circles. You are asked to take circle 1 and "move it" so that it is on top of circle 2. This process of moving is called a translation and can be thought of as sliding. You do this by ensuring that the two have the same center. So, starting at (-4,5) how do you have to move to end up at (2,1)?
To do this we need to move right 6 as the x-coordinate goes from -4 to 2. We also need to move down 4 as the y-coordinate goes from 5 to 1. So we add 6 to the x-coordinate and subtract 4 from the y-coordinate. The transformation rule is (x+6, y-4).
Once you do this the circles have the same center. Next you wish to dilate circle 1 so it ends up being the same size at circle 2. That means you stretch it out in such a way that it keeps its shape. Circle 1 has a radius of 2 centimeters and circle 2 has a radius of 6 centimeters. That is 3x bigger. So we dilate by a factor of 3.
Translations and dilations (along with reflections and rotations) belong to a group known as transformations.
Its -4/3
Thank You.
Pls mark Brainliest!
