Answer:
answer would be -2/5
Step-by-step explanation:
i think thats what you mean i hope this helps
The volume we're looking for is the volume of both cones in the figure.
The volume of a cone is
.
So,
.
<u>Cone 1's variables:</u>
r = 2.6
h = 5
<u>Cone 2's variables:</u>
r = 2.6
h = 3
Now we can just plug and chug!
![V_{tot} = [(3.14)(2.6^2)(\frac{5}{3} )] + [(3.14)(2.6^2)\frac{3}{3} )]\\V_{tot} = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_{tot} = (35.45) + (21.23)\\V_{tot} = 56.68](https://tex.z-dn.net/?f=V_%7Btot%7D%20%3D%20%5B%283.14%29%282.6%5E2%29%28%5Cfrac%7B5%7D%7B3%7D%20%29%5D%20%2B%20%5B%283.14%29%282.6%5E2%29%5Cfrac%7B3%7D%7B3%7D%20%29%5D%5C%5CV_%7Btot%7D%20%3D%20%5B%283.14%29%286.76%29%281.67%29%5D%20%2B%20%5B%283.14%29%286.76%29%281%29%5D%5C%5CV_%7Btot%7D%20%3D%20%2835.45%29%20%2B%20%2821.23%29%5C%5CV_%7Btot%7D%20%3D%2056.68)
V = c. 56.6 cubic units
Price of a bag of fertilizer increased from $8 t0 $15
thus the price increase = $7
% increase = 7/8 * 100 = 87.5%
in decimal = 0.875 divide by 100
in fraction = 875/1000
What? Lol I will lyk if I see him/her.