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LekaFEV [45]
3 years ago
14

sqrt \frac{256}{4\\}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0

Answer:

8

Step-by-step explanation:

\sqrt{\frac{256}{4} }

\sqrt{\frac{16*16}{2*2} }

\sqrt{(\frac{16}{2})^2 }

square and root gets cancel . so ,

\frac{16}{2}

8

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Factor x^2-2x-4 PLEASE ANSWER QUICKLY!!! I WILL GIVE POINTS!!! DBA IS TODAY!!!!
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To factor x²-2x-4, you are looking to answer three questions.

1) What pair of numbers multiplies to 4?

2) What pair of numbers multiplies to 1?

3) Do these pairs when multiplied together, add/subtract to the middle term?

To answer (1), our pairs are 2 and 2, 4 and 1. Since there's a negative with 4 at the end (from question one), the signs will be opposite.

To answer (2), only pair multiplies to 1 - 1 and 1. Let's try both pairs from 1.

(x-4)(x+1) The middle term here is -3x. Nope.

(x-1)(x+4). The middle term here is 3x. Nope.

(x-2)(x+2) The middle term is 0x (or no middle term). Nope.

So x²-2x-4 does not factor.

4 0
3 years ago
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3 0
3 years ago
Kinda confused on this one so it would be helpful to answer this for 30 points! And marked!
seropon [69]

Answer:

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Read 2 more answers
Quien me ayuda es suma de polinomios
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