1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ugo [173]
3 years ago
9

To decrease the rate of reaction you would ... *

Chemistry
2 answers:
STALIN [3.7K]3 years ago
4 0
Answer: it’s number 2 add a catalyst

Hopefully this helped :)
Nana76 [90]3 years ago
3 0
Decrease the concentration of a reactant
You might be interested in
Which element mo se na or br contains the most moles of atoms in a 1.0 gram sample?
Fittoniya [83]
To determine this, lets use the atomic mass for each element to determine the corresponding number of moles for a given mass of 1 g.

Mo: 95.94 g/mol
1 g/95.94 g/mol = 0.01042 moles Mo

Se: 78.96 g/mol
1 g/78.96 g/mol = 0.01266 moles Se

Na: 22.99 g/mol
1 g/22.99 g/mol = 0.0435 moles Na

Br: 79.9 g/mol
1 g/79.9 g/mol = 0.0125 moles Br

<em>Thus, the answer is Na.</em>
3 0
4 years ago
Why do we observe national day​
WITCHER [35]

A national day is a day on which celebrations mark the nationhood of a nation or state. It may be the date of independence, of becoming a republic, or a significant date for a patron saint or a ruler (such as a birthday, accession, or removal). The national day is often a public holiday.

5 0
3 years ago
An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the
maxonik [38]

Answer:

Molarity of KIO_{3} solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of KIO_{3} = 214 g/mol

So, 562 g of KIO_{3} = \frac{562}{214} moles of KIO_{3} = 2.63 moles of KIO_{3}

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is KIO_{3} and solvent is water

Total volume of solution is 4.30 L

So, molarity of KIO_{3} solution = \frac{2.63}{4.30}mol/L = 0.612 mol/L

3 0
3 years ago
It can take hundreds of billions of years for a red dwarf to convert all of its hydrogen completely to helium.
vodomira [7]
False, it takes less than 14 billion years to completely burn through its fuel.
4 0
3 years ago
The production of water proceeds according to the following equation.
dem82 [27]

Answer:

Place the reactants in a smaller container.

Explanation:

If you were to reduce the source of heat, the hydrogen and oxygen molecules would lose their kinetic energy, resulting in less collisions.

_______________________________________________________

Maintaining the same temperature of the reactants, the speed would neither increase nor decrease as temperature is directly proportional to the kinetic energy of the molecules, which in turn is directly proportional to the number of collisions. However, placing the reactants in a smaller container would result in less volume, and hence the molecules would collide with one another more often!

<u><em>Hope that helps!</em></u>

4 0
3 years ago
Other questions:
  • Why reducing power of elements decrease, on moving from left to right in a period?
    12·1 answer
  • A slow jogger runs a mile in 11 minutes. Calculate the speed in km/h
    5·1 answer
  • What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
    5·1 answer
  • Which statement best describes a possible way that
    14·1 answer
  • What is another name for neurons
    12·2 answers
  • Which statement is true if the delta h of a reaction is positive
    8·1 answer
  • How many kilojoules (kJ) in 373 joules (J)?
    14·1 answer
  • [Cr{P(CH2CH3)3}6]2(SO4)3​
    13·1 answer
  • Which of the following contains the greatest mass of oxygen?
    9·1 answer
  • The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!