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olga nikolaevna [1]
3 years ago
8

What is the density of a 6 g of pure copper with a volume of 12 mL?

Chemistry
1 answer:
Sati [7]3 years ago
5 0

Answer:

The density of copper is 0.5 g/mL

Explanation:

Given data:

Mass of copper = 6 g

Volume of copper = 12 mL

Density of copper = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

d = 6 g/ 12 mL

d = 0.5 g/mL

Thus, the density of copper is 0.5 g/mL

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Three chemical reactions of ethane?
Otrada [13]

Answer:

1.Hydrogenation of Alkenes and akynes.

2.Reaction of alkylhalides.

3. Halogenation.

6 0
2 years ago
A prion is an infectious self-reproducing protein structure. true or false
Alexandra [31]

Answer:

True is the correct answer.

Explanation:

  • The statement that a prion is an infectious, self-reproducing protein structure is true.
  • prion is an infectious particle and they do not have genetic material.
  • Prion present in the brain region that results in deadly neurodegenerative illnesses in humans and animals.
  • Prions are the self-producing proteinaceous infectious capable of transferring infection in the absence of the nucleic acids.
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8 0
3 years ago
16. As he developed his periodic table, Mendeleev grouped the elements lithium,
Aleonysh [2.5K]

Answer:

the reactivity and the valence electrons

Explanation:

the reactivity of the elements would have played a significant role in why such elements were grouped together. the number of valence electrons dictates how reactive an element is - the less valence electrons the more reactive it is. the column, group 1 in which these elements are put together in, show that each of the elements have 1 valence electrons and are therefore reactive.

you can go on to further explain what valence electrons are, explain what the group numbers are associated with the valence electrons and how valence electrons effect reactivity. further this, talk about how the three elements have the same number of valence electrons and therefore were grouped together

8 0
3 years ago
Calculate the number of moles of caco3 (calcium carbonate, or limestone) in a 20.0g sample of this substance
Brrunno [24]
First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.

     molar mass of CaCO₃ = (1 mol Ca)(40 g Ca/mol Ca) + (1 mol C)(12 g of C/1 mol of C) + (3 mols of O)(16 g O/1 mol O) = 100 g/mol of CaCO₃

Then, divide the given amount of substance by the calculated molar mass.
            number of moles = (20 g)(1 mol of CaCO₃/100 g)
             number of moles = 0.2 moles of CaCO₃

<em>Answer: 0.2 moles</em>
6 0
3 years ago
Heating 235 g of water from 22.6°C to 94.4°C in a microwave oven requires 7.06 × 104 J of energy. If the microwave frequency is
Darya [45]

Answer: 3.69 × 10^27

Explanation:

Amount of energy required = 7.06 × 10^4 J

Frequency of microwave (f) = 2.88 × 10^10 s−1

Planck's constant (h) = 6.63 × 10^-34 Jᐧs/quantum

Recall ;

Energy of photon = hf

Therefore, energy of photon :

(6.63 × 10^-34)j.s× (2.88 × 10^10)s^-1

= 19.0944 × 10^(-34 + 10) = 19.0944×10^-24 J

Hence, number of quanta required :

(7.06 × 10^4)J / (19.0944 × 10^-24)J

= 0.369 × 10^(4 + 24) = 0.369×10^28

= 3.69 × 10^27

6 0
3 years ago
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